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DochEvi [55]
3 years ago
14

Help plz and no link​

Chemistry
1 answer:
Vlad [161]3 years ago
7 0

Answer:

yum yummy

Explanation:

Mis-ka, Mou-ska

Mickey Mouse!

M-I-C-K-E-Y

M-O-U-S-E (that's me!)

M-I-C-K-E-Y

M-O-U-S-E

It's the Mickey Mouse Clubhouse

Come inside, it's fun inside

It's the Mickey Mouse Clubhouse (roll call!)

Donald (present!)

Daisy (here!)

Goofy (hyuck, here!)

Pluto (woof! woof!)

Minnie (hi, here!)

Mickey (right here!)

It's the Mickey Mouse Clubhouse

Come inside, it's fun inside

M-I-C-K-E-Y

M-O-U-S-E

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Knowing others is intelligence; knowing yourself is true wisdom. mastering others is strength; mastering yourself is true power. if you realize that you have enough, you are truly rich, "And the cause of not following your heart, is in spending the rest of your life wishing you had."

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Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
Nutka1998 [239]

Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

Molar mass of O2 = 32 g

Molar mass of PbO = 207 + 32 = 239 g

Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

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