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Lera25 [3.4K]
3 years ago
8

A student weighs out a 2.23 g sample of KF, transfers it to a 300 ml volumetric flask, adds enough water to dissolve it and then

adds water to the 300 mL tick mark What is the molarity of potassium fluoride in the resulting solution?
Chemistry
1 answer:
densk [106]3 years ago
7 0
Answer: i d8nt kn09.
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1-propanol (P1° = 20.9 Torr at 25 °C) and 2-propanol (P2° = 45.2 Torr at 25 °C) form ideal solutions in all proportions. Let x1
jekas [21]

Answer:

y1 = 0.3162

y2 = 0.6838

Explanation:

ok let us begin,

first we would be defining the parameters;

at 25°C;

1-propanol P1° = 20.90 Torr

2-propanol P2° = 45.2 Torr

From Raoults law:

P(1-propanol) = P⁰ × X(1-propanol)

P(1-propanol) = 20.9 torr × 0.45 = 9.405

P(1-propanol) = 9.405 torr

Also P(2-propanol) = P⁰ × X(2-propanol)

P(2-propanol) = 45.2 torr × 0.45

P(2-propanol) = 20.34 torr

but the total pressure = sum of individual pressures

total pressure = 9.405 + 20.34

total pressure = 29.745 torr

given that y1 and y2 represent the mole fraction of each in the vapor phase

y1 = P1 / total pressure

y1 = 9.405/29.745

y1 = 0.3162

Since y1 + y2 = 1

y2 = 1 - y1

∴ y2 = 1 -  0.3162

y2 = 0.6838

cheers, i hope this helps.

7 0
3 years ago
A substance is highly malleable and has a shiny luster. Which of the following best explains the probable position of the substa
Aleks04 [339]
The answer is D only metals are shiny and highly malleable
5 0
3 years ago
Read 2 more answers
What is the relationship between a chemical equation and a chemical reaction? What are reactants and products in a chemical equa
Sergio039 [100]

Answer:

A chemical reaction occurs when reactants are converted into products. A chemical equation is a representation of a chemical reaction using chemical symbols. The chemical equation also indicates the physical state of the reactants and products. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

Explanation: because UwU

5 0
2 years ago
A substance with a high [H ] would likely have which additional characteristics? a high [OHâ€"" ] and a high pOH a low [OHââ
viktelen [127]

The negative log function that determines the acidity or alkalinity by hydronium ion concentration is called pH.

The substance having high \rm [H] will have:

Option B. A low \rm [OH ^{-}] and a high \rm pOH

This characteristic can be explained as:

  • The concentrations of \rm [H^{+}] and \rm [OH ^{-}] are inversely dependent on each other so when the concentration of  raises then the concentration of \rm [OH ^{-}] drops and vice versa.

  • The pH of a solution or substance is calculated with the help of:

\rm  pH  = \rm - log  \rm [H^{+}]

From the formula, it can be deduced that when the concentration of \rm [H^{+}] is high then the pH has a low value and it means that the solution is acidic.

  • pH can also be written as:

\rm pH + pOH &= 14 \\\\\rm pOH &= 14 - pH

From this formula we can that when the value of pH is less then the value of pOH will be increased and vice versa.

Therefore, when pOH is in high concentration then \rm [OH ^{-}] is low.

To learn more about pH and pOH follow the link:

brainly.com/question/13557815

4 0
2 years ago
Assume that silver and gold form ideal, random mixtures. Calculate the mass of pure Ag needed to cause an entropy increase of 20
KengaRu [80]

Answer:

m_{Ag}=2,265.9g

Explanation:

Hello!

In this case, since the definition of entropy in a random mixture is:

\Delta S=-n_TR\Sigma[x_i*ln(x_i)]

For this silver-gold mixture we write:

\Delta S=-(n_{Au}+n_{Ag})R\Sigma[\frac{n_{Au}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Au}}{n_{Au}+n_{Ag}} )+\frac{n_{Ag}}{n_{Au}+n_{Ag}} *ln(\frac{n_{Ag}}{n_{Au}+n_{Ag}} )]

By knowing the moles of gold:

n_{Au}=100g*\frac{1mol}{197g} =0.508mol

It is possible to write the aforementioned formula in terms of the variable x representing the moles of silver:

20\frac{J}{mol}=-(0.508+x)8.314\frac{J}{mol*K} \Sigma[\frac{0.508}{0.508+x} *ln(\frac{0.508}{0.508+x} )+\frac{x}{0.508+x} *ln(\frac{x}{0.508+x} )]

Which can be solved via Newton-Raphson or a solver software, in this case, I will provide you the answer:

x=n_{Ag}=21.0molAg

So the mass is:

m_{Ag}=21.0mol*\frac{107.9g}{1mol}\\ \\m_{Ag}=2,265.9g

Best regards!

3 0
3 years ago
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