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Nadya [2.5K]
3 years ago
14

Which type of scientist would observe the spread of a species of red fire ants

Chemistry
1 answer:
diamong [38]3 years ago
7 0
It would be a biologist
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A vacuum gage connected to a chamber reads 35 kpa at a location where the atmospheric pressure is 92 kpa. determine the absolute
stealth61 [152]

Vacuum gage connected to a chamber reads 35 kpa at a location where the atmospheric pressure is 92 kpa then the  absolute pressure in the chamber and express is 57kpa

Gauge pressure is the pressure relative to atmospheric pressure. Gauge pressure is positive for pressures above atmospheric pressure, and negative for pressures and absolute pressure is the sum of gauge pressure and atmospheric pressure

Here to find absolute pressure atmospheric pressure=92kpa and  vacuum gage=35 kpa                                      

Pabsolute pressure=Patmospehric pressure - Pvaccume

92-35=57kpa

Know more about absolute pressure

brainly.com/question/28498660

#SPJ4

6 0
2 years ago
Earth is approximately 1.5x10^8 km from the sun. The speed of light is 3.0x10^8. How many minutes does it take for light to reac
Masteriza [31]
1.5 x 10^{8} mm = 1500 x 10^{8} m

1500 x 10^{8} / ( 3.0 x 10^{8} ) = 500 s

500/60 = 8.3 

So approximately it takes 8.5 minutes 


Hope that helps, Good luck! (:<span />
3 0
3 years ago
5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H
cricket20 [7]
We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572.  That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0
3 years ago
When a substance is heated ,the kinetic energy of its molecules
Simora [160]

Answer:

When a substance is heated ,the kinetic energy of its molecules also increase.

Explanation:

K.E is directly proportional to T

5 0
3 years ago
I neeeddddd heeeellllllppppp I'll give you brainliest
aev [14]

not double replacement

it will be synthesis

they are fusing the two elements

plz mark brainliest


3 0
3 years ago
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