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sveta [45]
3 years ago
8

Assume an object A mass of 36.240 g and it’s density is 5.40 g/mL. What is it’s volume

Chemistry
1 answer:
topjm [15]3 years ago
5 0

The volume of the object=6.71ml

Given:

Mass of the object=36.240g

Density of the object=5.40\frac{g}{m l}

To find:

Volume of the object

<u>Step by Step Explanation:</u>

Solution:

According to the formula, Density of the object is given as

\rho=\frac{m}{v} and from this volume can be derived as

v=\frac{m}{\rho}

Where, m=mass of the cylinder

\rho=density of the cylinder

v=volume of the cylinder

We know the values of m=36.240g and \rho=5.40\frac{g}{m l}

Substitute these values in the above equation we get

v=\frac{m}{\rho}

v=36.240/5.40

=6.71ml

Result:

Thus the volume of the object is 6.71ml

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These are four questions and four answers.

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1) activation energy of the reverse reaction

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2) Rate of the forward reaction

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<em>Activarion energy</em> is the energy required by the reactants to form the intermediate transition state and become products.

<em>Catalysts</em> are substances that change the path of the chemical reactions, lowering the activation energy, and thus speeding up the rate of the reactions, since the products can reach the new lower activation energy faster.

The equilibrium reactions are the chemical process in which two reactions, the <em>forward and the reverese reactions</em>, occur simultaneously and at the same rate.  The equlibrium reactions may be represented by:

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Where A → B is the direct or forward reaction, and A ← B is the reverse reaction (note the inversed arrow, from right to left).

For the direct reaction A represents the reactants and B represents the products. On the other hand, B represents the reactants and A represents the reactants of the reverse reaction and A. This, is A is the reactant of the forward reaction and the product of the reverse reaction, while B is the reactant of the reverse reaction and the product of the forward reaction.

Since, <em>the addition of a catalyst</em> lowers the activation energy of the process, the new activation energy is lower for both the forward and the reverse reaction, meaning that:

1. <em>The activation energy of the reverse reaction is decreased</em> (option b. of the first question)

2.<em> The rate of the forward reaction is increased</em> (option a. of the second question)

3. <em>The rate of the reverse reaction is increased</em> (option a. of the third question).

4. <em>Activation energy of the forward reaction is decreased</em> (option b. of the fourth question).

In summary, the addition of a catalyst decreases the activation energy for both forward and reverse reactions, and increases the rate of both forward and reverse reactions.

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