3.9L
Explanation:
Initial volume = 25L
Final volume = 28.9L
The initial volume is the volume of the liquid without the metal in originally in the container. It is 25L
After adding the metal, the volume changes to 28.9L
Final volume = Initial volume + volume of metal
To find the volume of metal make it the subject of the expression;
Volume of metal = Final volume - initial volume = 28.9 - 25 = 3.9L
The volume of irregular solids are measured by immersing them in water. The change in volume gives their volume.
Sometimes the volume of water displaced is the volume of the solid.
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Answer: B2H6 (g) + 3O2 (g) → B2O3 (s) + 3H2O (g) (ΔH = -2035 kJ/mol) 3H2O (g) → 3H2O (l) (ΔH = -132 kJ/mol) 3H2O (l) → 3H2 (g) + (3/2) O2 (g) (ΔH = 858 kJ/mol)
Explanation: ??
Answer:
it is salt an I right or not
Answer:
None of the options are correct. The correct answer is:
56.67g
Explanation:
N2 + 3H2 —> 2NH3
Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol
Mass of NH3 from the balanced equation = 2 x 17 = 34g
Molar Mass of H2 = 2x1 = 2g/mol
Mass of H2 from the balanced equation = 3 x 2 = 6g
From the equation,
6g of H2 produced 34g of NH3.
Therefore, 10g of H2 will produce = (10 x 34)/6 = 56.67g of NH3
Therefore, 56.67g of NH3 are produced
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