Is snails growing shell conserve mass

1 answer:

5 0

The thing that two changes have in common that snails growing shells and rust forming on a bicycle frame is option D. Both are caused by cooling.

<h3>How come snails develop shells?</h3>

Calcium carbonate is said to be the material that makes up the shell. The snail's shell expands as it grows to accommodate its growing body. Snails and slugs are also members of the mollusc family of creatures.

Therefore, note that air that has been mixed with the metal can make rust to develop. and as such, option D. Both are caused by cooling. is correct.

Learn more about snails growing shells from
brainly.com/question/15758489

#SPJ1

See full question below

What do these two changes have in common? snails growing shells rust forming on a bicycle frame Select all that apply.

A. Both are only physical changes.

B. Both are caused by heating.

C. Both are chemical changes.

D. Both are caused by cooling

You might be interested in

QUESTION 20

Assoli18 [71]

Answer:

49.56

Explanation:

5 0

3 years ago

____Cl2+____H2=____HCl

Genrish500 [490]

Answer:

H2 + 2 Cl2 = 2 HCl2

6 0

3 years ago

Which of the following statements best describes the relationships between carrying captivity in population size

Ierofanga [76]

The correct answer is letter a, whereas, carrying capacity in captivity increases population size. It is because the carrying captivity is the one responsible for having a maximum population size in which will help in sustaining the necessities that the species need in the environment in which makes it responsible for the population size to increase depending on its capacity. The correct answer is letter a.

4 0

4 years ago

1. Unas de las formas de producir nitrógeno gaseoso (N2) es mediante la oxidación de metilamina (CH3NH2), tal como se muestra en

Maslowich

Answer:

a) 4CH₃NH₂ + 9O₂ ⇄ 4CO₂ + 10H₂O + 2N₂

b) m = 5,043 g

c) % = 69,4 %

Explanation:

a) La ecuación balanceada es la siguiente:

4CH₃NH₂ + 9O₂ ⇄ 4CO₂ + 10H₂O + 2N₂

En el balanceo, se tiene en la relación estequiométrica que 4 moles de metilamina reacciona con 9 moles de oxígeno para producir 4 moles de dióxido de carbono, 10 moles de agua y 2 moles de nitrógeno.

b) Para determinar la masa de nitrógeno se debe calcular primero el reactivo limitante:

$n_{O_{2}} = \frac{m}{M} = \frac{25,6 g}{31,99 g/mol} = 0,800 moles$

$n_{CH_{3}NH_{2}} = \frac{4}{9}*0,800 moles = 0,356 moles$

De la ecuación anterior se tiene que la cantidad de moles de metilamina necesaria para reaccionar con 0,800 moles de oxígeno es 0,356 moles, y la cantidad de moles iniciales de metilamina es 0,5 moles, por lo tanto el reactivo limitante es el oxígeno.

Ahora, podemos calcular la masa de nitrógeno producida:

$n_{N_{2}} = \frac{2}{9}*n_{O_{2}} = \frac{2}{9}*0,8 moles = 0,18 moles$