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Naya [18.7K]
11 months ago
5

Is snails growing shell conserve mass

Chemistry
1 answer:
postnew [5]11 months ago
5 0

The thing that two changes have in common that snails growing shells and  rust forming on a bicycle frame is option D. Both are caused by cooling.

<h3>How come snails develop shells?</h3>

Calcium carbonate is said to be the material that makes up the shell. The snail's shell expands as it grows to accommodate its growing body. Snails and slugs are also members of the mollusc family of creatures.

Therefore, note that  air that has been mixed with the metal can make rust to develop. and as such, option D. Both are caused by cooling. is correct.

Learn more about snails growing shells from
brainly.com/question/15758489

#SPJ1

See full question below

What do these two changes have in common? snails growing shells rust forming on a bicycle frame Select all that apply.

A. Both are only physical changes.

B. Both are caused by heating.

C. Both are chemical changes.

D. Both are caused by cooling

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Answer:

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Explanation:

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3 years ago
List the first 20 elements chemistry
timama [110]

Answer:

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890J of heat are applied to a piece of aluminum, causing a 4.6°C increase in its temperature. The specific heat of aluminum is 0
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Answer:

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2 years ago
The density of lead is 11.4g/cm3. What volume, in ft3, would be occupied by 10.0 g of lead?
yawa3891 [41]

Answer:

3.10×10¯⁵ ft³.

Explanation:

The following data were obtained from the question:

Density (D) of lead = 11.4 g/cm³

Mass (m) of lead = 10 g

Volume (V) of lead =.?

Density (D) = mass (m) / Volume (V)

D = m/V

11.4 = 10 / V

Cross multiply

11.4 × V = 10

Divide both side by 11.4

V = 10 / 11.4

V = 0.877 cm³

Finally, we shall convert 0.877 cm³ to ft³. This can be obtained as follow:

1 cm³ = 3.531×10¯⁵ ft³

Therefore,

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0.877 cm³ = 3.10×10¯⁵ ft³

Thus, 0.877 cm³ is equivalent to 3.10×10¯⁵ ft³.

Therefore, the volume of the lead in ft³ is 3.10×10¯⁵ ft³.

7 0
2 years ago
Find the % of H in ammonium hydroxide (NH4OH)
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Total number of atoms = 7

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2 years ago
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