<span>Each die has 6 faces, and the odds of a 6 or 1 showing up are 1 in 6.
So, there are several possible victory conditions:
1 of the 4 dice shows a 1, and none show 6.
2 of the dice show one and one or none show 6.
3 of the dice show one, and 2 or less show 6.
All 4 dice show 6.
There are 1296 possible combinations of dice that could be rolled.
So, the probabilities are as follows.
4 in 81 1 of the 4 dice shows a 1, and none show 6.
1 in 81 2 of the dice show one and one or none show 6.
5 in 1296 3 of the dice show one, and the 4 th die result doesn't matter, as long as it isn't 1.
1 in 1269 - All 4 dice show 6.
So,there is a 43 in 648 chance of this occurring.</span>
21/25 would be the answer
Answer: you have no questions up and there is not a picture but I can help you with t/f questions
Step-by-step explanation:
Answer:
B. $96.04
Step-by-step explanation:
112.99 - 15%=96.04
