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Andrei [34K]
3 years ago
8

In one circuit, the terminals are at 98V and 100V. In the second circuit, they are at 2V and 6V. Why does the 2V and 6V produce

a stronger electric field?
Physics
1 answer:
Svetach [21]3 years ago
3 0

The potential difference between circuit 1 = 100V - 98V

                                                                      = 2V

The potential difference between circuit 2 = 6V - 2V

                                                                       = 4V

According to Ohm's law,

ΔV = RI

where,

ΔV is the potential difference

R is the resistance

I is the current

We can see that potential difference is directly proportional to the current i.e., greater the potential difference, greater will be the current and thus more will be the electric field.

And as per the potential difference of the two circuits, circuit 2 has greater potential difference than the circuit 1.

So, the circuit 2 will have greater produce stronger electric field.

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State the ohm's law in words​
Anton [14]

Explanation:

Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and directly proportional to the resistance of the circuit. The formula for Ohm's law is V=IR.

5 0
3 years ago
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The annoying sound from a mosquito is produced when it beats its wings at the average rate of 600 wingbeats per second. What is
podryga [215]
Frequency is given by the formula cycles÷seconds

So if the mosquito can complete 600 cycles in one second, our formula will be

f=600÷1
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The frequency is 600 Hz
6 0
3 years ago
Constants A capacitor is connected across an ac source that has voltage amplitude 59 0 V and frequency 77 0 Hz Part C What is th
Vladimir79 [104]

Answer:

C = 1.77 \times 10^{-4} F

Explanation:

As we know that in AC circuit we have

V = i x_c

here we have

V = 59 V

i = 5.05 A

so we will have

x_c = \frac{59}{5.05}

x_c = 11.68 ohm

also we know that

x_c = \frac{1}{\omega C}

here we will have

11.68 = \frac{1}{(2\pi 77)C}

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7 0
3 years ago
A copper rod of length 27.5 m has its temperature increases by 35.9 degrees celsius. how much does its length increase?(unit=m)
gavmur [86]
<h2>The increase in length = 1.87 x 10⁻²</h2>

Explanation:

When copper rod is heated , its length increases

The increase in length can be found by the relation

L = L₀ ( 1 + α ΔT )

here L is the increased length and L₀ is the original length

α  is the coefficient of linear expansion and ΔT is the increase in temperature .

The increase in length = L - L₀ = L₀ x α ΔT

Substituting all these value

Increase in length = 27.5 x 1.7 x 10⁻⁵ x 35.9

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5 0
3 years ago
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kap26 [50]

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Explanation:

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v = 340m/s (speed of sound in air)

vs = velocity of the source of sound.

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but f1 = 80Hz

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substituting,

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vs = 453.33 - 340

vs = 113.33m/s

velocity of the car is 113.33m/s

5 0
3 years ago
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