Answer:3.92475J
Explanation:
ideal gas equation
PV=nrT
P=pressure
V=volume 9*5*14=630m^3
n=mole
Mole=mass/molecular mass
molecular mass of air=28.1g/mol
R=gas constant
T=temperature in kelvin
1.01*10^5*630=(m/28)*8.314j/molK *273K
784959.5677356082g
784.95kg
Kinetic energy=0.5*m*v^2
Velocity of air
0.5*784.95kg*0.1^2
K.E=3.92475J
6
Answer:
distance =13km , displacement=3km
Explanation:
north south does not affect displacement
Answer:
By decreasing the resistance
You should calculate 40 kg and the radius 3mm.
To solve this problem it is necessary to apply the concepts related to the orbital velocity of a satellite on earth.
This concept is expressed in the equation,

Where,
G = Universal Gravitational constant
Mass of the Earth
Therefore the ratio of the velocity from two satellites is,

The ratio between the two satellites is the same, then



Therefore the correct option is B.