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4 years ago

How long does it take for light from the sun to reach earth

Physics

2 answers:

enot [183]4 years ago

7 0

8 minutes because I searched on the internet and it said so

MrRa [10]4 years ago

5 0

8 minutes and 20 seconds

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A message is sent from the Galileo spacecraft orbiting Jupiter to earth at a distance of 928,000,000km. If it took the signal 51

expeople1 [14]

The answer would approximately be 299,741.60

6 0

3 years ago

Read 2 more answers

A charge of +1.4×10^6 coulombs moves from point a to b. What is the potential difference between the two points if the work done

Rama09 [41]

The potential difference between the two points if the work done on the charge is +3.4×10^7 joules would be A. 10volts.

8 0

3 years ago

a vehicle starts from rsst and after 10 seconds its velocity is 20m/s find the acceleration and the distance travelled.(step by

Naily [24]

Answer:

Acceleration is 2 m/s²

Distance is 100 m

Explanation:

From definition of acceleration, Acceleration is the rate of change in velocity.

• Simplifying the definition, or modifying it;

${ \boxed{ \rm{acceleration = \frac{(final \: velocity - initial \: velocity)}{time} }}}$

• Let's formulate symbols:

${ \boxed{ \rm{a = \frac{v - u}{t} }}}$

a is acceleration
v is final velocity, v = 20 m/s
u is initial velocity, u = 0 m/s [ at rest ]
t is time, t = 10 seconds

${ \rm{a = \frac{20 - 0}{10} = \frac{20}{10} }} \\ \\{ \boxed{ \rm{ \: a = 2 \: {ms}^{ - 2} }}}$

Distance = ut + ½at²

Distance = (0 × 10) + (½ × 2 × 10²)

Distance = 0 + 10²

Distance = 100 meters

8 0

3 years ago

20 kg who is running at a speed of 4.0 m/s jumps onto a stationary sled of mass 5.0 kg on a frozen lake. the speed at which the

Step2247 [10]

Here we can use momentum conservation as there is no external force on sled and child while he jump on sled

by momentum conservation equation

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v{2f}$

$20*4 + 5*0 = 20*v + 5 *v$

since sled and child both moves with same speed so here they both will have same final speed "v"

by solving above equation we will have

25 v = 80

v = 3.2 m/s

So they will move together with speed 3.2 m/s

6 0

3 years ago

A boat initially traveling at 10. meters per second accelerates uniformly at the rate of 5.0 meters per second2 for 10. seconds.

guajiro [1.7K]

The initial speed of the boat is $v_0=10 m/s$
and its acceleration is $a=5.0 m/s^2$
Since the boat is moving by uniform accelerated motion, the distance covered by the boat in a time t=10 s is given by:
$S(t)=v_0 t + \frac{1}{2}at^2 = (10 m/s)(10 s)+ \frac{1}{2}(5m/s^2)(10s)^2 =350 m$
So, the boat covers a distance of 350 m in 10 seconds.

4 0

4 years ago