You get a tub of warm water and tip the warm water into the cold water
1: viewing any chemical reaction in a laboratory
2: dangerous to look at when it burns & used in photography, fireworks, and flares
3: the product
<u>Answer:</u> The standard potential of the cell is 0.77 V
<u>Explanation:</u>
We know that:

The substance having highest positive
reduction potential will always get reduced and will undergo reduction reaction.
The half reaction follows:
<u>Oxidation half reaction:</u> 
<u>Reduction half reaction:</u>
( × 2)
To calculate the
of the reaction, we use the equation:

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.
Putting values in above equation follows:

Hence, the standard potential of the cell is 0.77 V
A neutral atom becomes a negatively charged ion by accepting electrons.
For example:
F + e⁻ → F⁻
S + 2e⁻ →S²⁻