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3 years ago

Which of the following is deforestation most likely to cause?

Chemistry

1 answer:

Sliva [168]3 years ago

4 0

Answer:

Explanation:

trees (as well as other plants) produce carbon dioxide. deforestation is the removal of trees. this will not cause an increase in any pollutants such as ozone. ozone is made from VOCs and other harmful pollutants, and not caused by trees. tearing down trees will also not create more soil. So the answer has to be C

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The respiratory system is what brings in food and breaks it down True or false

Gala2k [10]

Answer:

false

Explanation:

the respiratory system includes the lungs and heart

not food

5 0

3 years ago

Consider the following reaction: CHCl3(g) + Cl2(g) → CCl4(g) + HCl(g) The initial rate of the reaction is measured at several di

Ira Lisetskai [31]

Answer : The correct rate law for the reaction is,

$\text{Rate}=k[CHCl_3][Cl_2]^{1/2}$

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$CHCl_3(g)+Cl_2(g)\rightarrow CCl_2(g)+HCl(g)$

Rate law expression for the reaction:

$\text{Rate}=k[CHCl_3]^a[Cl_2]^b$

where,

a = order with respect to $CHCl_3$

b = order with respect to $Cl_2$

Expression for rate law for first observation:

$0.0035=k(0.010)^a(0.010)^b$ ....(1)

Expression for rate law for second observation:

$0.0069=k(0.020)^a(0.010)^b$ ....(2)

Expression for rate law for third observation:

$0.0098=k(0.020)^a(0.020)^b$ ....(3)

Expression for rate law for fourth observation:

$0.027=k(0.040)^a(0.040)^b$ ....(4)

Dividing 1 from 2, we get:

$\frac{0.0069}{0.0035}=\frac{k(0.020)^a(0.010)^b}{k(0.010)^a(0.010)^b}\\\\2=2^a\\a=1$

Dividing 2 from 3, we get:

$\frac{0.0098}{0.0069}=\frac{k(0.020)^a(0.020)^b}{k(0.020)^a(0.010)^b}\\\\1.42=2^b\\b=\frac{1}{2}$

Calculation used :

$1.42=2^b\\\log (1.42)=b\log 2\\\log (\frac{1.42}{2})=b\\b=0.5=\frac{1}{2}$

Thus, the rate law becomes:

$\text{Rate}=k[CHCl_3]^1[Cl_2]^{1/2}$

7 0

3 years ago

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant

Vanyuwa [196]

<h3>Answer:</h3>

Excess Reagent = NBr₃

<h3>Solution:</h3>

The Balance Chemical Equation for the reaction of NBr₃ and NaOH is as follow,

2 NBr₃ + 3 NaOH → N₂ + 3 NaBr + 3 HBrO

Calculating the Limiting Reagent,

According to Balance equation,

2 moles NBr₃ reacts with = 3 moles of NaOH

So,

40 moles of NBr₃ will react with = X moles of NaOH

Solving for X,

X = (40 mol × 3 mol) ÷ 2 mol

X = 60 mol of NaOH

It means 40 moles of NBr₃ requires 60 moles of NaOH, while we are provided with 48 moles of NaOH which is Limited. Therefore, NaOH is the limiting reagent and will control the yield of products. And NBr₃ is in excess as some of it is left due to complete consumption of NaOH.

6 0

3 years ago

At what temperature will 2.50 moles of ideal

Sever21 [200]

Answer: 1,218K

Explanation:

7 0

3 years ago

BONUS QUESTION - It takes 194 mL of a 0.5 M NaOH solution to neutralize 300

Strike441 [17]

Answer:

1.7 mol/dm3

Explanation:

working out in the image

6 0

3 years ago