Answer:
KJ8RT898TGHO7-6734354546746R476
Explanation:
The reducing agent will itself be oxidized.
The oxidation number of carbon goes form 0 to +2. Therefore, it is the reducing agent.
Answer:
Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃
Step-by-step explanation:
The unbalanced equation is
Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + KNO₃
Notice that the complex groups like NO₃ and CrO₄ stay the same on each side of the equation.
One way to simplify the balancing is to replace them with a single letter.
(a) For example, let <em>X = NO₃</em> and <em>Y =CrO₄</em>. Then, the equation becomes
PbX₂ + K₂Y ⟶ PbY + KX
(b) You need 2X on the right, so put a 2 in front of KX.
PbX₂ + K₂Y ⟶ PbY + 2KX
(c) Everything is balanced. Now, replace X and Y with their original meanings. The balanced equation is
Pb(NO₃)₂ + K₂CrO₄ ⟶ PbCrO₄ + 2KNO₃
Answer:
Pentasulfur nonanitride.
Explanation:
In order to name a compound properly, we need to identify the type of a compound we have. The given compound consists of two non-metals, sulfur and nitrogen. This implies that we have a covalent compound in contrast to an ionic compound which consists of a metal and a non-metal.
To name a molecular/covalent compound, we should use prefixes stating the number of atoms we have. In this case, we have 5 sulfur atoms. The prefix for 5 is 'penta'. That said, we have 'pentasulfur' as our beginning of the name.
We also have 9 nitrogen atoms. The second atom in the molecular formula would have an ending of '-ide', so we expect to have 'nitride'. Adding a prefix for 9, we'd have 'nonanitride'.
Putting everything together, the name is pentasulfur nonanitride.
Some common prefixes:
mono – one (we don't state mono for the first atom, e. g., we would name CO as carbon monoxide instead of monocarbon monoxide);
di – two;
tri – three;
tetra – four;
penta – five;
hexa – six;
hepta – seven;
octa – eight;
nona – nine;
deca – ten.
Notice that 'decanitride' would be correct in case you had 10 nitrogen atoms, similarly, tetra and hexa stand for 4 and 6 instead of 5 given sulfur atoms.
Since Oxygen is in group 16, this element has 6 valence electrons. Valence electrons like to become as stable as possible and similar to a noble gas, which has 8 electrons. You need to find an element that will transfer its atoms to the oxygen to make 8 electrons. Looking at the periodic table, Selenium is in group 16 and will have 6 valence electrons (6 + 6 = 12). This can't transfer electrons with Oxygen. Hydrogen is in group 1 with 1 valence electron (6 + 1 = 7). This can't transfer electrons with Oxygen. Strontium is in group 2 with 2 valence electrons (6 + 2 = 8). This will transfer electrons to Oxygen, making it the most stable.
The answer is O and Sr.
