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DENIUS [597]
3 years ago
14

8. Why do we see water droplets on the outer surface of a glass containing ice cold water?

Chemistry
2 answers:
baherus [9]3 years ago
5 0

Answer:

8. We see water droplets on the outer surface of a glass containing ice cold water because condensation is happening! This happens when warm water vapour from the surroundings come into contact with a cool surface (in this case the cool glass) and loses heat and condenses, forming water droplets on the surface of the glass.

9 a) -248.15 celcius

b) 99.85 celcius

10. by using 2 syringes, one filled with water and one filled with air. when you compress it, you will find that the one with water barely compresses and the one filled with air should be able to be compressed quite a bit. and to the extent that the syringe is unable to be pushed down further, that is the maximum compressibility of air.

guapka [62]3 years ago
4 0

Answer:

hshdjsaksknhcbxbbaabbdbxbfvv x x xnznxkflfdpappaaplsxlfmfnfnncc

Explanation:

jsjsjdjfhdhahahajssjxnnfncncnfnfdnkdskdkkxjgjgjkdkaka

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What happened during the Renaissance that encouraged progress in the study of matter?
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If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcoho
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If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcohol evaporate? If some liquid remains, how much will there be? The vapor pressure of ethyl alcohol at 25 °C is 59 mm Hg, and the density of the liquid at this temperature is 0.785g/cm^3 .

will all the alcohol evaporate? or none at all?

Answer:

Yes, all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore  be zero.

Explanation:

Given that:

The volume of alcohol which is placed in a small laboratory = 1.0 L

Vapor pressure of ethyl alcohol  at 25 ° C = 59 mmHg

Converting 59 mmHg to atm ; since 1 atm = 760 mmHg;

Then, we have:

= \frac{59}{760}atm

= 0.078 atm

Temperature = 25 ° C

= ( 25 + 273 K)

= 298 K.

Density of the ethanol = 0.785 g/cm³

The volume of laboratory = l × b × h

= 3.0 m × 2.0 m × 2.5 m

= 15 m³

Converting the volume of laboratory to liter;

since 1 m³ = 100 L; Then, we  have:

15 × 1000 = 15,000 L

Using ideal gas equation to determine the moles of ethanol in vapor phase; we have:

PV = nRT

Making n the subject of the formula; we have:

n = \frac{PV}{RT}

n = \frac{0.078 * 15000}{0.082*290}

n = 47. 88 mol of ethanol

Moles of ethanol in 1.0 L bottle can be calculated as follows:

Since  numbers of moles = \frac{mass}{molar mass}

and mass = density × vollume

Then; we can say ;

number of moles = \frac{density*volume }{molar mass of ethanol}

number of moles =\frac{0.785g/cm^3*1000cm^3}{46.07g/mol}

number of moles = \frac{&85}{46.07}

number of moles = 17.039 mol

Thus , all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.

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