All categories

2 years ago

8. Why do we see water droplets on the outer surface of a glass containing ice cold water?

Chemistry

2 answers:

baherus [9]2 years ago

5 0

Answer:

8. We see water droplets on the outer surface of a glass containing ice cold water because condensation is happening! This happens when warm water vapour from the surroundings come into contact with a cool surface (in this case the cool glass) and loses heat and condenses, forming water droplets on the surface of the glass.

9 a) -248.15 celcius

b) 99.85 celcius

10. by using 2 syringes, one filled with water and one filled with air. when you compress it, you will find that the one with water barely compresses and the one filled with air should be able to be compressed quite a bit. and to the extent that the syringe is unable to be pushed down further, that is the maximum compressibility of air.

guapka [62]2 years ago

4 0

Answer:

hshdjsaksknhcbxbbaabbdbxbfvv x x xnznxkflfdpappaaplsxlfmfnfnncc

Explanation:

jsjsjdjfhdhahahajssjxnnfncncnfnfdnkdskdkkxjgjgjkdkaka

You might be interested in

Specific gravity of a vegetable oil is 0.85. What is its density?

elena-s [515]

I think its density is 850kg/m^3

6 0

2 years ago

A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and wa

timofeeve [1]

The answer you are looking for would be a colliod. Hope this helps have a great day!!

6 0

3 years ago

Read 2 more answers

Scientists believe that there are three genes that contribute to skin color in humans.

Darina [25.2K]

Answer:B

Explanation:

I took the test

4 0

3 years ago

Read 2 more answers

How do metals become stable?

natali 33 [55]

Answer:

Atoms of metal elements give away electrons in their reactions to form positive ions. The ions formed have a full outer electron shell, so are very stable.

Explanation:

To become stable, the metal atom wants to get rid of one or more electrons in its outer shell. ... Alternately, an atom that loses electrons becomes a positively charged ion (aka cations). The particles in an ionic compound are held together because there are oppositely charged particles that are attracted to one another.

8 0

3 years ago

The benzoate ion, c6h5coo− is a weak base with kb=1.6×10−10. how many moles of sodium benzoate are present in 0.50 l of a soluti

lyudmila [28]

$NaC6H5COO \rightarrow Na{^{+}} + C6H5COO^{-}$

Here the base is a benzoate ion, which is a weak base and reacts with water.

$C6H5COO^{-}(aq) + H2O (l)\leftrightarrow C6H5COOH(aq)+ OH^{-}(aq)$

The equation indicates that for every mole of OH- that is produced , there is one mole of C6H5COOH produced.

Therefore [OH-] = [C6H5COOH]

In the question value of PH is given and by using pH we can calculate pOH and then using pOH we can calculate [OH-]

pOH = 14 - pH

pH given = 9.04

pOH = 14-9.04 = 4.96

pOH = -log[OH-] or $[OH^{-}] = 10^{^{-pOH}}$

$[OH^{-}] = 10^{^{-4.96}}$

$[OH^{-}] = 1.1\times 10^{-5}$

The base dissociation equation kb = $\frac{Product}{Reactant}$

$kb =\frac{[C6H5COOH][OH^{-}]}{[C6H5COO^{-}]}$

H2O(l) is not included in the 'kb' equation because 'solid' and 'liquid' are taken as unity that is 1.

Value of Kb is given = $1.6\times 10^{-10}$

And value of [OH-] we have calculated as $1.1\times 10^{-5}$ and value of C6H5COOH is equal to OH-

Now putting the values in the 'kb' equation we can find the concentration of C6H5COO-

$kb =\frac{[C6H5COOH][OH^{-}]}{[C6H5COO^{-}]}$

$1.6\times 10^{-10} = \frac{[1.1\times 10^{-5}][1.1\times 10^{-5}]}{[C6H5COO^{-}]}$

$[C6H5COO^{-}] = \frac{[1.1\times 10^{-5}][1.1\times 10^{-5}]}{1.6\times 10^{-10}}$

$[C6H5COO^{-}] = 0.76 M$ or $0.76\frac{mol}{L}$

So, Concentration of NaC6H5COO would also be 0.76 M and volume is given to us 0.50 L , now moles can we calculated as : Moles = M X L

Moles of NaC6H5COO would be = $0.76(\frac{mol}{L}) \times (0.50L)$

Moles of NaC6H5COO (sodium benzoate) = 0.38 mol

8 0

3 years ago

Read 2 more answers