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2 years ago

8. Why do we see water droplets on the outer surface of a glass containing ice cold water?

Chemistry

2 answers:

baherus [9]2 years ago

5 0

Answer:

8. We see water droplets on the outer surface of a glass containing ice cold water because condensation is happening! This happens when warm water vapour from the surroundings come into contact with a cool surface (in this case the cool glass) and loses heat and condenses, forming water droplets on the surface of the glass.

9 a) -248.15 celcius

b) 99.85 celcius

10. by using 2 syringes, one filled with water and one filled with air. when you compress it, you will find that the one with water barely compresses and the one filled with air should be able to be compressed quite a bit. and to the extent that the syringe is unable to be pushed down further, that is the maximum compressibility of air.

guapka [62]2 years ago

4 0

Answer:

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Explanation:

jsjsjdjfhdhahahajssjxnnfncncnfnfdnkdskdkkxjgjgjkdkaka

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Write an equation for the reaction in which h2c6h7o5- acts as a base

Alexeev081 [22]

H 2 c6 = HC 8
O 5 - HC 8 = hco 3

4 0

2 years ago

179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g

taurus [48]

Answer:

the specific heat of the unknown compound is $c_u=0.412J/g \cdot C$

Explanation:

Generally the change in temperature of water is evaluated as

$\Delta T = T_2 -T_1$

Substituting 16.1°C for $T_1$ and 27.4°C for $T_2$

$\Delta T = 27.4 - 16.1$

$=11.3^oC$

Generally the change in temperature of unknown compound is evaluated as

$\Delta T_u = T_3 -T_2$

Substituting 27.4°C for $T_2$ and 94.3°C for $T_3$

$\Delta T = 94.3 - 27.4$

$=66.9^oC$

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

$H_w = mc_w \Delta T$

Substituting 179.1 g for m , 4.18 J/g.C for $c_w$ (specific heat of water)

$H_w = 4.18 * 179.1 * 11.3$

$= 8459.6J$

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

$H_u = m_uc_u \Delta T_u$

By conservation of energy law

Heat lost = Heat gained

Substituting 306.9 g for $m_u$ , 8459.6J for $H_u$

$8459.6 = 306.9 * c_u * 66.9$

Therefore $c_u = \frac{8459.6}{308.9 *66.9}$

$=0.412J/g \cdot C$

4 0

3 years ago

A sample compound contains 9.11 g Ni and 5.89g F. What is the empirical formula of this compound?

Alexxx [7]

The empirical formula of the compound is C. NiF₂.

Step 1. Calculate the moles of each element

The empirical formula is the simplest whole-number ratio of atoms in a compound.

The ratio of atoms is the same as the ratio of moles.

So, our job is to calculate the molar ratio of Ni to F.

Moles of Ni = 9.11 g Ni × (1 mol Ni /(58.69 g Ni) = 0.1552 mol Ni

Moles of F = 5.89 g F × (1 mol F/19.00 g F) = 0.3100 mol F

Step 2. Calculate the molar ratio of the elements

Divide each number by the smallest number of moles

Ni:F = 0.1552:0.3100 = 1:1.997 ≈ 1:2

Step 3: Write the empirical formula

EF = NiF₂

8 0

3 years ago

Read 2 more answers

What is the purpose of the stairstep pattern on the periodic table of the elements?

Mamont248 [21]

Answer: The bold staircase in the periodic table allows us to classify which elements are metalloids.

Explanation: Additionally, it acts like a "divider" that allows us to properly distinguish the metals from the non-metals in the periodic table.

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7 0

2 years ago

How much heat is needed to boil 45 grams of water at 100°C?

wolverine [178]

Answer:

Depends how much water and the temperature of the water. To heat 1 mL of water by 1 degree C 1 cal of energy (4.184 Joules) is required. Assuming that the water is at 25 degrees C, to boil one litre (liter) of water you would require 75,000 cal or 313.8 kJ.

6 0

3 years ago