Answer: Stealth scanning technique
Explanation:
Stealth scanning technique consist of the following types of scans :
1. FIN scan
2. X- MAS tree scan
3. NULL scan
The FIN scan responds by considering port open if response in received for its packet sent with the fin flag else considered closed.
The X-MAS tree scan fires up by setting a TCP packet with URG, PUSH, FIN flags and the port is considered open if no response.
NULL scans sends null packet and considers it to be an open port.
Stealth scanning techniques considers to get some response from the network with out actually using a handshaking and is used to bypass firewall rules, logging mechanism, and hide themselves as usual network traffic.
Rebooting the computer and calling the computer maunfactoring company will help. If not, you could go to a repair shop.
Answer:
class Main {
public static void main(String args[]) {
Deque<Integer> stack = new ArrayDeque<Integer>();
Random rand = new Random();
for(int i=0; i<10; i++) {
int n = rand.nextInt(100);
System.out.printf("%02d ", n);
stack.push(n);
}
System.out.println();
while(stack.size() > 0) {
System.out.printf("%02d ", stack.removeFirst());
}
}
}
Explanation:
example output:
31 18 11 42 24 44 84 51 03 17
17 03 51 84 44 24 42 11 18 31
Answer:
a) 10
b) 1
C) 10
D) 1
E) 20
F) 10
Explanation:
a) The largest number of records that could appear in one bin
= 10
B) The smallest number of records that could appear in one bin
= 1
C) The largest number of records that cab appear in one bin
= 10
d) smallest number
= 1
e) With frequency = 20. the largest number of records that could appear in one bin with equal width discretization (10 bins)
= 20
f ) with equal height discretization
= 10
<span>D. all of the above is the answer
</span>
