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2 years ago

8

Jenn can rake the yard in 4.75 hours. Kathy can do the raking job in 7 hours. How long will it both girls working together?

1 answer:

d1i1m1o1n [39]2 years ago

5 0

Answer:

4.75 hour

Step-by-step explanation:

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7. If x can be any number, how many solutions are there for the equation? y = 7x – 1 * A. There are two solutions because there

Hitman42 [59]

For the function y = 7x - 1, if you state that the domain(or all the numbers you can substitute in for "x") of that function is the set of all real numbers, then you can assume that there will be an infinite number of solutions for the function.

In other words, if you substitute any real number in for "x" you will find that you will get a corresponding value for "y". In fact, these "pairs" of corresponding values of x and y are called ordered pairs and represent the various solutions of the equation.

Your response should be choice D:

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3 years ago

What is the value of xy/z if x = -1, y = -10 and z = 2?

AlekseyPX

$\frac{ - 1 \times ( - 10)}{2} = \frac{10}{2} = 5$

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3 years ago

I NEED HELP WITH THIS PROBLEM......

Sonja [21]

Roger is 17 :) have a nice day :)

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2 years ago

Read 2 more answers

Directions: Choose the letter of the correct answer.

Bezzdna [24]

Answer:

Step-by-step explanation:

1) y = 3x -------------(I)

y = 4x - 5 -------------(II)

Plug in y= 3x in equation (II)

3x = 4x - 5

3x + 5 = 4x

5 = 4x - 3x

5 = x

x= 5

Plug in s = 5 in equation (I)

y = 3*5 = 15

x = 5

y = 15

4 0

3 years ago

The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2

Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in $^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15$ ways.

The probability of getting two 3 as outcome is $\frac{1}{4} \times\frac{1}{4} = \frac{1}{16}$ .

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is $1 - \frac{1}{4} = \frac{3}{4}$ .

Hence, the required probability is $15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}$ ≅0.2966 or, 0.23.

4 0

3 years ago