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hjlf
3 years ago
15

What are the 27 vawels

Physics
2 answers:
Gwar [14]3 years ago
7 0
If you mean Vowel...there are 5 vowels, A,E,I,O,U. Sometimes the letter Y can be a vowel too; it just depends on the word.
ruslelena [56]3 years ago
5 0

Answer:

umm i really don't know... sorry

Explanation:

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Which organism in the food web above is sometimes a first-level consumer and sometimes a second-level consumer?Explain
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The answer is: Mouse/Herbivore.

First organism is always a producer (plant) such as grass.
The 2nd organism is the first level or primary consumer. Ex. Mouse - It eats the producer, so it is a herbivore. 
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In the equation for Ohm’s law what does I stand for?
Ket [755]
A) current 

(I is always current in electricity)
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What is torque in physics ?
irina [24]

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Torque is a measure of the force that can cause an object to rotate about an axis.

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f the CD rotates clockwise at 500 rpmrpm (revolutions per minute) while the last song is playing, and then spins down to zero an
vazorg [7]

Answer:

The magnitude of the angular acceleration is  a =  20.14 rad/s^2

Explanation:

From the question we are told that

   The angular speed of CD is  w_{CD} =  500 rpm =  \frac{500  rpm}{\frac{60 \ s }{1 \ min} } * \frac{2 \pi }{ 1 \ rev} = 52.37 rad/s

    time taken to decelerate is t_{CD} =  2.60\ s

    The final angular speed is  w_f= 0 \ rad/s

The angular acceleration is mathematically represented as

         a =  \frac{w_f - w_{CD}}{t}

substituting values

          a =  \frac{0 - 52.37}{2.60}

         a =  - 20.14 rad/s^2

The negative sign show that the CD is decelerating  but the magnitude is

       a =  20.14 rad/s^2

   

3 0
3 years ago
The viewing screen in a double-slit experiment with monochromatic light. Fringe C is the central maximum. The fringe separation
makvit [3.9K]

Answer:

<em>Part A</em><em>:</em>

a) If the wavelength of the light is decreased the fringe spacing Δy will decrease.

<em>Part B</em><em>:</em>

b) If the spacing between the slits is decreased the fringe spacing Δy will increase.

<em>Part C</em><em>:</em>

a) If the distance to the screen is decreased the fringe spacing will decrease.

<em>Part D</em><em>:</em>

The dot in the center of fringe E is 920\ x\ 10^{-9} m farther from the left slit than from the right slit.

Explanation:

In the double-slit experiment there is a clear contrast between the dark and bright fringes, that indicate destructive and constructive interference respectively, in the central peak and then is less so at either side.

The position of bright fringes in the screen where the pattern is formed can be calculated with

                      \vartriangle y =\frac{m \lambda L}{d}

                      m=0,\pm 1,\pm 2,\pm 3,.....

  1. m is the order number.
  2. \lambda is the wavelength of the monochromatic light.
  3. L is the distance between the screen and the two slits.
  4. d is the distance between the slits.
  • Part A:  a) In the above equation for the position of bright fringes we can see that if the wavelength of the light \lambda is decreased the overall effect will be that the fringes are going to be closer. That means that the fringe spacing Δy will decrease.
  • Part B:  b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
  • Part C:  a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.
  • Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at  the center of the fringe E in the screen we use the condition for constructive interference. That says that the  path length difference Δr between rays coming from the left and right slit must be \vartriangle r=m \lambda

        We simply replace the values in that equation :

                      \vartriangle r= m \lambda =2.\ 460\ nm

                      \vartriangle r= 920\ x\ 10^{-9} m

         The dot in the center of fringe E is 920\ x\ 10^{-9}m farther from the left slit than from the right slit.

     

       

       

     

3 0
3 years ago
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