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Fed [463]
3 years ago
10

Why is mercury not suitable as the liquid in the U-tube? (the relationship between density of the liquid and the pressure in the

liquid)​
Physics
1 answer:
adoni [48]3 years ago
8 0
Mercury Is more suitable than water cause it is denser than water.

Relation between density and pressure

Pressure = force/area

Replace force by mass * acceleration
Pressure = mass * acceleration/ area

We can replace mass by density * volume since density = mass/ volume
Pressure = density * volume * acceleration/ area

Volume is length^3 whereas area is length ^2. So volume / area = length

Pressure = density * length * acceleration

Gravity is form of acceleration so

Pressure = density * length * gravity
Length can be height or depth

Finally pressure = density * height * gravity

P = ρ g h => pressure of liquid
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A ball of mass 0.5kg is thrown at a man of mass 59.5kg standing on roller skates, at a speed of 5 m/s. It is stopped by the man.
Akimi4 [234]

The final velocity of the man standing on roller skates with the ball caught, after it is thrown at him at a speed of 5 m/s, is 0.042 m/s.                        

 

The velocity of the man with the ball can be calculated by conservation of linear momentum:

p_{i} = p_{f}

m_{b}v_{b_{i}} + m_{m}v_{m_{i}} = m_{b}v_{b_{f}} + m_{m}v_{m_{f}}

Where:

m_{b}: is the mass of the ball = 0.5 kg

m_{m}: is the <u>mass</u> of the man = 59.5 kg

v_{b_{i}}: is the initial velocity of the <u>ball</u> = 5 m/s

v_{m_{i}}: is the <u>initial velocity</u> if the <u>man</u> = 0 (he is standing still)

v_{b_{f}}: is the final velocity of the <u>ball</u> =?

v_{m_{f}}: is the <u>final velocity</u> of the <u>man</u> =?

Since the man catches the ball, his final velocity is the same that the final ball's velocity, so:

m_{b}v_{b_{i}} + m_{m}v_{m_{i}} = v_{f}(m_{b} + m_{m})

v_{f} = \frac{m_{b}v_{b_{i}} + m_{m}v_{m_{i}}}{m_{b} + m_{m}} = \frac{0.5 kg*5 m/s + 0}{0.5 kg + 59.5 kg} = 0.042 m/s

Therefore, the velocity of the man with the ball is 0.042 m/s.

Learn more about the conservation of linear momentum here:  

  • brainly.com/question/2141713?referrer=searchResults
  • brainly.com/question/14283213?referrer=searchResults

I hope it helps you!  

4 0
2 years ago
A 2000 kg car moves down a level highway under the actions of two forces. one is a 1060 n forward force exerted on the drive whe
kipiarov [429]
Refer to the diagram shown below.

The net force acting on the vehicle is
F - R = 1060 -1010 = 50 N

The distance traveled is 21 m. Because the force is constant, the work done is
W = (50 N)*(21 m) = 1050 J

Assume that energy is not dissipated by air resistance or otherwise.
Conservation of energy requires that W = KE, where KE is the kinetic energy of the vehicle.
The KE is
KE = (1/2)*(2000 kg)*(v m/s)² = 1000v² J

Equate KE and W to obtain
1000v² = 1050
v² = 1.05
v = 1.025 m/s

Answer: 1.025 m/s

3 0
4 years ago
Is glass an insulator ​
krek1111 [17]
Yes glass is an insulator
3 0
4 years ago
Read 2 more answers
The de Broglie wavelength of a 0.064-kg golf ball is 3.09 x 10^−34m. What is its speed? (h = 6.63 x 10^−34 J⋅s)
tatyana61 [14]

Answer:

The speed is 33.5 m/s.

Explanation:

Given that,

Mass = 0.064 kg

Wavelength \lambda= 3.09\times10^{-34}\ m

We need to calculate the speed

Using formula of he de Broglie wavelength

\lambda=\dfrac{h}{mv}

v=\dfrac{h}{m\lambda}

Where, h = Planck constant

m = mass

\lambda = wavelength

Put the value into the formula

v = \dfrac{6.63\times10^{-34}}{0.064\times 3.09\times10^{-34}}

v=33.5\ m/s

Hence, The speed is 33.5 m/s.

3 0
3 years ago
What processes were involved in the formation of the model? How is the model similar to the real metamorphic sample? How is the
timurjin [86]
Metamorphic Rock - Forms when pressure, temperature, or chemical processes change existing rock. Igneous Rock - forms when magma or lava cools and hardens to become solid. Sedimentary Rock - Form when minerals that form from solutions or sediment from older rocks get pressed and cemented together. The three main rock types are igneous, metamorphic and sedimentary. The three processes that change one rock to another are crystallization, metamorphism, and erosion and sedimentation. Common metamorphic rocks include phyllite, schist, gneiss, quartzite and marble. Hope this helps!
7 0
3 years ago
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