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Fofino [41]
3 years ago
7

PLEASE HELP!! I'LL MARK U BRAINIEST!! ALSO PLZ IF YOU CAN SHOW THE WORK

Chemistry
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

9.63×10²⁴ particles of H₂O

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

From the balanced equation above,

1 mole of CH₄ reacted to produce 2 moles of H₂O.

Next, we shall determine the number of mole of H₂O produced by the reaction of 8 moles of CH₄. This can be obtained as follow:

From the balanced equation above,

1 mole of CH₄ reacted to produce 2 moles of H₂O.

Therefore, 8 moles of CH₄ will react to produce = 8 × 2 = 16 moles of H₂O.

Thus, 16 moles of H₂O were obtained from the reaction.

Finally, we shall determine the number of particles of H₂O produced. This can be obtained as follow:

Number of mole of H₂O produced = 16 moles

Number of particles produced =?

From Avogadro's hypothesis,

1 mole = 6.02×10²³ particles

Therefore,

16 mole = 16 mole × 6.02×10²³ particles / 1 mole

16 moles = 9.63×10²⁴ particles

Therefore, 9.63×10²⁴ particles of H₂O were produced.

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4 years ago
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7 0
3 years ago
A 232-lb fullback runs the 40-yd dash at a speed of 19.8 ± 0.1 mi/h.
Neporo4naja [7]

Answer:

(a)  7.11 x 10⁻³⁷ m

(b)  1.11 x 10⁻³⁵ m

Explanation:

(a)  The de Broglie wavelength is given by the expression:

λ = h/p = h/mv

where h is plancks constant, p is momentum which is equal to mass times velocity.

We have all the data required to calculate the wavelength, but first we will have to convert the velocity to m/s, and the mass to kilograms to work in metric system.

v = 19.8 mi/h x ( 1609.34 m/s ) x ( 1 h / 3600 s ) = 8.85 m/s

m = 232 lb x ( 0.454 kg/ lb ) = 105.33 kg

λ = h/ mv = 6.626 x 10⁻³⁴ J·s / ( 105.33 kg x 8.85 m/s ) = 7.11 x 10⁻³⁷ m

(b) For this part we have to use the uncertainty principle associated with wave-matter:

ΔpΔx > = h/4π

mΔvΔx > = h/4π

Δx = h/ (4π m Δv )

Again to utilize this equation we will have to convert the uncertainty in velocity to m/s for unit consistency.

Δv = 0.1 mi/h x ( 1609.34 m/mi ) x ( 1 h/ 3600 s )  

     = 0.045 m/s

Δx = h/ (4π m Δv ) = 6.626 x 10⁻³⁴ J·s / (4π x 105.33 kg x 0.045 m/s )

     = 1.11 x 10⁻³⁵ m

This calculation shows us why we should not be talking of wavelengths associatiated with everyday macroscopic objects for we are obtaining an uncertainty of 1.11 x 10⁻³⁵ m for the position of the fullback.

5 0
3 years ago
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So,

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6 0
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