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Nuetrik [128]
3 years ago
8

Decide which element probably has a boiling point most and least similar to the boiling point of potassium.

Chemistry
1 answer:
larisa86 [58]3 years ago
4 0

Explanation:

  • The boiling point of Potassium is most similar to the element sodium , since , both the elements belong to the same group i.e. , the group one , Hence , the most of the physical chemical properties are same , irrespective of some exceptions .

Hence , the Boiling point of Potassium and sodium are the same .

  • The boiling point of Potassium is least similar to the element helium , since , both the elements belong to different groups , Since , Helium has a negative boiling point and is one of the most stable element , being a noble gas .
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Explanation:

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A

Explanation:

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1. Mixing is a physical change.<br> True or false
Hitman42 [59]

Answer:

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Choose ALL TRUE statements about calorimetry from the choices below:
Ostrovityanka [42]

Answer:

True statment

2) Styrofoam would make a good calorimeter

3) Insulating material would make a good calorimeter

Explanation:

The calorimeter is one which is insulated that is which will not absorb or let the heat to escape from it. the calorimeter is used to measure the heat change during a process so if it will allow to exchange heat with surrounding it will deviate the readings or observence.

Copper is a good conductor of heat so we cannot use it make a calorimeter.

Hence

1) Copper would make a good calorimeter : False

2) Styrofoam would make a good calorimeter: True

Styrofoam is a bad conductor or insulator so it can be and it is used for calorimeter.

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6 0
3 years ago
g A gas is compressed in a cylinder from a volume of 20.0 L to 2.0 L by a constant pressure of 10.0 atm. Calculate the amount of
Lemur [1.5K]

Answer:

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

Explanation:

Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).

The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:

W system= -p*∆V

Where:

  • W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)
  • p: Pressure. Its unit of measurement in the International System is the pascal (Pa)
  • ∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)

In this case:

  • p= 10 atm= 1.013*10⁶ Pa (being 1 atm= 101325 Pa)
  • ΔV= 2 L- 20 L= -18 L= -0.018 m³ (being 1 L=0.001 m³)

Replacing:

W system= -1.013*10⁶ Pa* (-0.018 m³)

Solving:

W system= 18234 J

<u><em>The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.</em></u>

5 0
3 years ago
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