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3 years ago

Decide which element probably has a boiling point most and least similar to the boiling point of potassium.

Chemistry

1 answer:

larisa86 [58]3 years ago

4 0

Explanation:

The boiling point of Potassium is most similar to the element sodium , since , both the elements belong to the same group i.e. , the group one , Hence , the most of the physical chemical properties are same , irrespective of some exceptions .

Hence , the Boiling point of Potassium and sodium are the same .

The boiling point of Potassium is least similar to the element helium , since , both the elements belong to different groups , Since , Helium has a negative boiling point and is one of the most stable element , being a noble gas .

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Convert 5.28 x 1019 molecules of C6H1206 to grams.

nlexa [21]

Answer:

$m=0.0158g$

Explanation:

Hello there!

In this case, it is possible to comprehend these mass-particles problems by means of the concept of mole, molar mass and the Avogadro's number because one mole of any substance has 6.022x10²³ particles and have a mass equal to the molar mass.

In such a way, for C₆H₁₂O₆, whose molar mass is about 180.16 g/mol, the referred mass would be:

$m=5.28x10^{19}molecules*\frac{1mol}{6.022x10^{23}molecules}*\frac{180.16g}{1mol}\\\\m=0.0158g$

Best regards!

5 0

3 years ago

When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol

oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, $O_2$

Solution : Given,

Moles of $FeCl_3$ = 3.00 mole

Moles of $O_2$ = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)$

From the balanced reaction we conclude that

As, 2 moles of $FeCl_3$ react with 1 mole of $O_2$

So, 3.00 moles of $FeCl_3$ react with $\frac{3.00}{2}=1.5$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $FeCl_3$ is a limiting reagent and it limits the formation of product.

Hence, the reagent present in excess and remains unreacted is, $O_2$

4 0

3 years ago

A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

Zarrin [17]

Answer: Empirical formula is $C_2H_5O$

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

Step 1 : Converting each of the given masses into their moles by dividing them by Molar masses.

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = $\frac{330g}{12g/mol}=27.5moles$

Moles of Hydrogen = $\frac{69.5g}{1g/mol}=69.5moles$

Moles of Oxygen = $\frac{220.2g}{16g/mol}=13.76moles$

Step 2: Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

$\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2$

$\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5$

$\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1$

Step 3: Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = $C_2H_5O$

7 0

3 years ago

What electron configuration represents Nitrogen? A. 2,2 B. 2,8,4 C. 2,4 D. 2,5

Anastaziya [24]

Answer:

D. 2:5

Explanation:

It has 5 valency electrons

$.$

7 0

3 years ago

A mechanism for the decomposition of ozone is (2 O3 â†’ 3 O2). O3 â‡Œ O2 + OO + O3 â†’ O2 + O2What is the molecularity for the f

Gnesinka [82]

Answer:

The correct answer is option c.

Explanation:

Molecularity is defined as number of atoms , ions or molecules that must collide with one another so as to result in a chemical reaction.It is simply the sum of molecules of different reactants as represented in balanced chemical equation.

Reaction taking place in one step are said to be elementary reaction.

Reaction taking place in more than one step are said to be complex reaction.

A mechanism for the decomposition of ozone is given as:

1) $O_3 \rightarrow O_2 + O$

Molecularity for the first elementary reaction is 1. This because single ozone molecule is present.

2) $O + O3\rightarrow O_2 + O_2$

Molecularity for the second elementary reaction is 2. This because single ozone molecule reacts with 1 oxygen atom.

3 0

3 years ago