I think your answer is “true”, sorry if I’m wrong and hope this helps
Molality is one way of expressing concentration for solutions. It has units of moles of solute per kg of solvent. From the given values, we easily calculate for the moles of solute by multiplying the mass of solvent to the molality. We do as follows:
moles solute = 0.3 (10) = 3 mol solute
Answer:
KBr is limiting reactant.
Explanation:
Given data:
Mass of KBr =4g
Mass of Cl₂ = 6 g
Limiting reactant = ?
Solution:
Chemical equation:
2KBr + Cl₂ → 2KCl + Br₂
Number of moles of KBr:
Number of moles = mass/molar mass
Number of moles = 4 g/ 119 gmol
Number of moles = 0.03 mol
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 6 g/ 70 gmol
Number of moles = 0.09 mol
Now we will compare the moles of reactant with product.
KBr : KCl
2 : 2
0.03 : 0.03
KBr : Br₂
2 : 1
0.03 : 1/2×0.03= 0.015
Cl₂ : KCl
1 : 2
0.09 : 2/1×0.09 = 0.18
Cl₂ : Br₂
1 : 1
0.09 : 0.09
Less number of moles of product are formed by the KBr thus it will act as limiting reactant while Cl₂ is present in excess.
Answer:
NO2 is the molecular formula of nitrogen Oxide
Explanation:
Correct question
An oxide of nitrogen contain its own volume of nitrogen
its vapour dentity is 23. Find the molecular formula
Of nitrogen Oxide
Solution
As we know
Molecular Weight is equal to two times the vapour density
Hence, the molecular weight of Oxide of nitrogen is 2 * 22 = 44
Molecular weight of Oxide of nitrogen is the sum of atomic weight of nitrogen and oxygen
Molecular weight of Oxide of nitrogen = 14 + 16 *Y
14 + 16 *Y = 46
Y = 2
Hence, the formula is NO2
