Answer:
76.5g is present in 2.55mol of diazine
Explanation:
no. of mole equals mass over molar mass
molar mass of diazine equals 30g/mol.. then substitute to get the mass in grams which is 76.5g
Answer:definition group 17, halogens top right on the periodic table
Explanation:
I’m looking at it
Answer:
1.6605 × 10⁻²³ g / atom , 9.99 amu
Explanation:
Atoms present in 1 mole = 6.022 × 10²³ atoms
Given that
Moles of common Eastern mole = 8.3 moles
So,
Atoms in 8.3 moles are:
8.3 moles = 6.022 × 10²³ × 8.3 atoms
Also,
Average mass = Mass of the sample / Number of atoms
Mass of sample = 83 g
Average mass = 83 g / 6.022 × 10²³ × 8.3 atoms = 1.6605 × 10⁻²³ g / atom
In amu :
1 amu = 1.66 × 10⁻²⁴ g / atom
So,
Average mass = 1.6605 × 10⁻²³ / 1.66 × 10⁻²⁴ amu = 9.99 amu
Answer:
The molar mass of the metal is 54.9 g/mol.
Explanation:
When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.
Patm = Pwater + PH₂
PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar
The pressure of H₂ is:

The absolute temperature is:
K = °C + 273 = 25°C + 273 = 298 K
We can calculate the moles of H₂ using the ideal gas equation.

Let's consider the following balanced equation.
M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)
The molar ratio of M:H₂ is 1:1. So, 9.81 × 10⁻³ moles of M reacted. The molar mass of the metal is:

Answer:
It is one single unit which is repeated in a polymer