The answer is 
You must make sure each reactant has the same amount of subscripts on both sides of the equation.
You must make sure each reactant has the same amount of subscripts on both sides of the equation.
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0.58 is the molarity of 29.9 g of MgS in 911 mL of solution.
Define the molarity of a solution.
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
Given data:
Volume of solution = 911 mL=0.911L
Given the mass of MgS = 29.9 g
Molar mass of MgS = 56.38 g/mol
Moles of MgS = 0.5303299042
Molality = 0.5821403998=0.58
Hence, 0.58 is the molarity of 29.9 g of MgS in 911 mL of solution.
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Answer: The number of moles of produced are, 0.287 moles.
Explanation : Given,
Mass of = 14.9 g
Molar mass of = 32 g/mol
First we have to calculate the moles of
Now we have to calculate the moles of
The balanced chemical equation is:
From the reaction, we conclude that
As, 13 mole of react to give 8 moles of
So, 0.466 mole of react to give
mole of
Therefore, the number of moles of produced are, 0.287 moles.