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zavuch27 [327]
3 years ago
8

What would happen if prey was removed from the food web need asap

Chemistry
2 answers:
Simora [160]3 years ago
7 0
If any animal was removed from the food web, the animals that it would prey on would overpopulate and the animals that hunted it would stave because it has nothing to feed on. Hope this answers your question.
Ray Of Light [21]3 years ago
3 0
If prey were to be removed from the food web, that would cause the predators of the prey to eventually die off.
I hope this helped! :-)
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What is the mass of H2O
Dovator [93]

Answer:

The exact molecular mass is 18.01528 g/mol

Explanation:

Find this by adding the molecular masses of two hydrogen atoms and one oxygen atom.

8 0
3 years ago
Hydrogen is used as a rocket fuel because it is very light and reacts explosively and completely with oxygen. For the combustion
777dan777 [17]

Answer:

1. K<10−3

Explanation:

Equilibrium Constant is an expression which involves the concentration of the product divided by the concentration of the reactant molecules.

However the concentration of the pure liquid and pure solid is regarded as 1.

Equilibrium expression for the equation 2H2(g)+O2(g)⇌2H2O(g)

Equilibrium Constant = [H2O]^2/[H2]^2 x [O2]

Since H2O is a pure liquid, its concentration = 1

There fore;

Equilibrium Constant = 1/[H2]^2 x [O2]

This shows that the Equilibrium Constant of the equation will be less than 1 and greater than 0.

7 0
3 years ago
The reactants of two chemical equations are listed.
hjlf
The correct answer is b
8 0
2 years ago
A cup of black coffee has a pH of 5. What is the hydrogen Ion
alexandr1967 [171]
<span>pH = -log(H+ concentration)
so pH = -log(1.0 X 10^4)
</span><span>10^-4?
</span>
If this helped and you have any other questions, feel free to comment on my wall. Hope this helped.
8 0
3 years ago
if I add water to 170 mL of a 0.40 M KOH solution until the final volume is 375 mL, what will the molarity M of the diluted solu
nasty-shy [4]

4.7 M It may be wrong, but I hope it helps!

Explanation:

When you're diluting a solution, you're essentially keeping the number of moles of solute constant while changing the total volume of the solution.

Now, let's assume that you don't know the equation for dilution calculations.

In this case, you can use the molarity and volume of the concentrated solution to determine how many moles of hydrochloric acid you start with.

c

=

n

V

⇒

n

=

c

⋅

V

n

HCl

=

18 M

⋅

190

⋅

10

−

3

L

=

3.42 moles HCl

You then add water to get the total volume of the solution from  

190 mL

to  

730 mL

.

The number of moles of hydrochloric acid remains unchanged, which means that the molarity of the diluted solution will be

c

=

3.42 moles

730

⋅

10

−

3

L

=

4.7 M

8 0
2 years ago
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