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svlad2 [7]
3 years ago
5

Abhfguojgedfhoobdssghjbhjjbjkjjk friends ?

Chemistry
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

yessss what's ur snapp?

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What are the branch-chain Alkanes?
snow_tiger [21]

Answer:

The top branch-chain is a Isobutane branch. And the bottom branch chain is a  Neopentane branch

7 0
3 years ago
Read 2 more answers
Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
Kipish [7]

Answer:

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

Moles of NaOH = \frac{15.0 g}{40 g/mol}=0.375 mol

Molarity of the nitric acid solution = 0.250 M

Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

Molarity=\frac{Moles}{Volume(L)}

n=0.250 M\times 0.150 L=0.0375 mol

NaOH+HNO_3\rightarrow NaNO_3+H_2O

According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

\frac{1}{1}\times 0.0375 mol of NaOH

Moles of NaOH left unreacted  in the solution =

= 0.375 mol - 0.0375 mol = 0.3375 mol

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

Then 0.3375 moles of NaOH will give :

1\times 0.3375 moles=0.3375 mol of hydroxide ion

The molarity of hydroxide ion in solution ;

=\frac{0.3375 mol}{0.150 L}=2.25 M

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

3 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.314 kg of water?
Mariulka [41]

Answer:

g NaCl = 424.623 g

Explanation:

<em>C</em> NaCl = 3.140 m = 3.140 mol NaCl / Kg solvent

∴ solvent: H2O

∴ mass H2O = 2.314 Kg

mol NaCl:

⇒ mol NaCl = (3.140 mol NaCl/Kg H2O)×(2.314 Kg H2O) = 7.266 mol NaCl

∴ mm NaCl = 58.44 g/mol

⇒ g NaCl = (7.266 mol NaCl)×(58.44 g/mol) = 424.623 g NaCl

5 0
3 years ago
Which pair of reactants will undergo aldol condensation to produce methylvinyl ketone?
xenn [34]

When formaldehyde and acetone then react with each other( aldol condensation) then it will be formed <u> methyl vinyl ketone.</u>

<u />

In organic chemistry, an aldol condensation would be a condensation reaction in which an enol and enolate ion combines with a carbonyl chemical to produce a -hydroxy aldehyde or -hydroxy ketone, that is then dehydrated to produce a conjugated enone.

In aldol condensation, when  formaldehyde and acetone then react with each other then it will be formed <u> </u><u>methyl vinyl ketone.</u>

It can be written as

CH_{2} O + CH_{3} COCH_{3} → HOCH_{2} -CH_{2} -CO-CH_{3}

When it will be heated then it gives methyl vinyl ketones.

HOCH_{2} -CH_{2} -CO-CH_{3} → CH_{2} =CH-CO-CH_{3}

So, the pair of reactants will be formaldehyde and acetone

To know more about aldol condensation

brainly.com/question/9415260

#SPJ4

6 0
1 year ago
During the formation of a chemical bond between two hydrogen atoms, which of the following statements is always true?
Wewaii [24]

A) Energy is released during the formation of the bond.

Explanation:

During the formation of a chemical bonds between two hydrogen atoms, energy is always released during the formation of this bond type.

Bond formation process is usually exothermic and energy is released during the formation of the bond.

  • Bond breaking process is an endothermic process in which energy is absorbed from the surrounding.
  • Whenever a bond is broken, the bond energy value is positive but when a bond is formed, the bond energy value is given a negative sign.

For a bond formation process in which hydrogen atoms are bonded covalently, energy is usually released.

Learn more:

Enthalpy changes brainly.com/question/10567109

#learnwithBrainly

5 0
3 years ago
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