<span>The answer is electrical energy. This is the energy freshly resulting from electric potential energy or kinetic energy. When lightly used to label energy engaged or perhaps brought by an electrical circuit (for instance, one providing by an electric power usefulness) "electrical energy" talks about energy which has been transformed from electric potential energy. </span>
An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reducedExamples of oxidizing agents include halogens, potassium nitrate, and nitric acid. A reducing agent, or reductant, loses electrons and is oxidized in a chemical reaction. A reducing agent is typically in one of its lower possible oxidation states, and is known as the electron donor.
Answer:
Explanation:
given mass = 697 g
molar mass = mass of H × mass of N × 3 × mass of O
= 1 × 14 × 3 × 16 = 672 g
no. of moles = given mass / molar mass = 697 / 672 = 1.03 moles
Hope this helps
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About 1.051 moles (depends on how u round it)
Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.
Solution:- The balanced equation for the combustion of acetylene is:

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

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The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.
From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

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Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.
So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

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