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rosijanka [135]
3 years ago
15

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.4

3 m/s2, what is the radius of the circle?
A.0.60 m
B.1.2 m
C.0.36 m
D.0.84 m
Chemistry
2 answers:
Leokris [45]3 years ago
8 0

Answer:

The radius of the circle is 0.60 meters.

Explanation:

It is given that,

Speed of squirrel, v = 0.51 m/s

Centripetal acceleration, a=0.43\ m/s^2  

Let r be the radius of circle. The expression for centripetal acceleration is given by :

a=\dfrac{v^2}{r}

r=\dfrac{v^2}{a}

r=\dfrac{(0.51\ m/s)^2}{0.43\ m/s^2}

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.

Lelu [443]3 years ago
3 0
I believe It's A. You really should check other sites like before using your points. Just a little pro tip! Another tip: give me brainliest answer pls.
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A series circuit has two 5.0-ohm resistors and a power source of 9.0 volts. How will the current be affected and what will it be
miskamm [114]
The formula for solving current given with resistance and power source or voltage is shown below:
I = V/R  

When two 5 ohms resistors are in series, we have:
I = 9 volts / (5+5 ohms)
I = 0.9 amperes

When it is being added with another 7.5 resistors, we have:
I = 9 volts / (5+5+7.5 ohms)
I = 0.529 ampere

The answer to the question is the letter "D. decrease; 0.51 amps".
3 0
3 years ago
What is the acceleration of a ball traveling horizontally with an initial velocity of 20 meters/second and, 2.0 seconds later, a
Pepsi [2]

Answer: <em>Acceleration of the ball in the given system is 5 meter per Second Square</em>

<em>The laws of motion are used to determine various aspects of an object in motion</em>.

Explanation:

Applying the first law of motion to calculate acceleration; if formula used in first law is given as v=u+at

Here we have a final velocity as 40 meter per second and initial velocity as 20 meter per second and time span is given as 2 second applying the given values in the given equation and finding the value of a

                            30=20+a \times 2 = a=5 m/s^2

6 0
3 years ago
The mass percentage of hydrochloric acid within a solution is 28.00%28.00% . Given that the density of this solution is 1.1411.1
sashaice [31]

Answer:

8.76M

Explanation:

Given that

Mass from the density = 1141g

According to the given situation the computation of molarity of the solution is shown below:-

we will took HCL solution which is 1000mL

HCl = 28% by mass

So,

Mass of HCl in 1-litre solution is

= \frac{28}{100} \times 1141

Which gives the result of molar mass HCI is

= 319.48g /mol

Now,

Molarity is

= \frac{319.48}{36.45}

Which gives results of molarity is

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8 0
3 years ago
Calculate the mass of .0605 moles of crystalline sucrose. Sucrose is C12 H22 O11 . The molar mass is __________ g/mole. Show you
KengaRu [80]

Answer:

20.7g/mol

Explanation:

7 0
3 years ago
(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain
Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

6 0
3 years ago
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