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aleksandr82 [10.1K]
3 years ago
14

onsider the isomerization of butane with an equilibrium constant of . The system is originally at equilibrium with [butane] = 1.

0 M and [isobutane] = 2.5 M. a If 0.60 mol/L of isobutane is suddenly added and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas? = M = M

Chemistry
1 answer:
Alborosie3 years ago
5 0

Answer:

The equilibrium concentration of Butane = 1.17 molar and isobutane = 2.93 molar

Explanation:

Consider equilibrium constant for the isomerisation reaction of butane and isobutane at 25⁰C = 2.5

                         

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Answer:

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Explanation:

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The diagram illustrates the water cycle.
MissTica

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2 years ago
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Hey there!:

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4 0
3 years ago
Convert 1000mg=__g 1L=__mL 160cm=__mm 1.4km=__m 109g=__kg 250m=__km 80cm=__m 75mL=__L 5.6m=__cm 6.5g=__mg 170.4m=__cm 564Dg=__g
Snowcat [4.5K]

Answer:

1000mg= 1g

1L= 1000 mL

160cm = 1600mm

1.4km= 1400m

109 g = 0.109kg

250m= 0.250 km

80cm= 0.8 m

75mL= 0.075L

5.6m= 560 cm

6.5g= 6500mg

170.4m= 17040 cm

564 Dg = 5640 g

58 dg = 5800 mg

600 L=  0.6 KL

0.0923Km= 92300 mm

Explanation:

1 mg = 1x10⁻³ g

1 g = 1000 mg

1 g = 10 dg

1 g = 1x10⁻³ kg

1 Dg = 10 g

1 dg = 100 mg

1 L = 1000 mL

1 L = 1x10⁻³ KL

1 mL = 1x10⁻³ L

1 km = 1000 m

1 km = 1x10⁶ mm

1 m = 1x10⁻³ km

1 cm = 1x10⁻² m

1 cm = 10 mm

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How did gus get ao gay ??
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Magic, that how

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