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aleksandr82 [10.1K]
3 years ago
14

onsider the isomerization of butane with an equilibrium constant of . The system is originally at equilibrium with [butane] = 1.

0 M and [isobutane] = 2.5 M. a If 0.60 mol/L of isobutane is suddenly added and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas? = M = M

Chemistry
1 answer:
Alborosie3 years ago
5 0

Answer:

The equilibrium concentration of Butane = 1.17 molar and isobutane = 2.93 molar

Explanation:

Consider equilibrium constant for the isomerisation reaction of butane and isobutane at 25⁰C = 2.5

                         

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6Ce^{4+} + I^- + 6OH^- → 6Ce^{3+} + IO_3^- + 3H_2O is the balanced chemical equation.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

Half-reaction method:

Unbalanced chemical equation:

Ce^{4+} + I^-→ Ce^{3+} + IO^{3-}

Oxidation half-reaction:

I^-+ 6OH^- - 6e- → IO^{3-} + 3H_2O

Reduction half-reaction:

Ce4^+ + e^- → Ce^{3+}

Balanced chemical equation:

6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO^{3-} + 3H_2O

Oxidation number method:

Unbalanced chemical equation:

Ce^{4+} + I^-→ Ce^{3+} + IO^{3-}

I^{-1} -6e^-→ I^{+5}

Ce^{4+} + e^- → Ce^{3+}

Balanced chemical equation:

6Ce^{4+} + I^{-1} → 6Ce^{3+} + I^{+5}

or

6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO_3^- + 3H_2O

Hence, 6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO_3^- + 3H_2O is the balanced chemical equation.

Learn more about the balanced chemical equation here:

https://brainly.in/question/46754758

#SPJ1

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