onsider the isomerization of butane with an equilibrium constant of . The system is originally at equilibrium with [butane] = 1.
0 M and [isobutane] = 2.5 M. a If 0.60 mol/L of isobutane is suddenly added and the system shifts to a new equilibrium position, what is the equilibrium concentration of each gas? = M = M
1 answer:
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<u>Answer:</u>
<u>For a:</u> The amount of heat transferred for the given amount of methanol is 94.6736 kJ.
<u>For b:</u> The mass of methane gas produced will be 10.384 g.
<u>Explanation:</u>
For the given chemical reaction:
- <u>For a:</u>
To calculate the number of moles, we use the equation:
......(1)
Given mass of methanol = 24.0 g
Molar mass of methanol = 32.04 g/mol
Putting values in above equation, we get:
By Stoichiometry of the reaction:
For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.
So, for every 0.749 moles of methanol, the amount of heat transferred will be =
Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.
- <u>For b:</u>
By Stoichiometry of the reaction:
252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.
So, 82.1 kJ of energy will be absorbed when = of methane gas is produced.
Now, calculating the mass of methane gas from equation 1, we get:
Molar mass of methane gas = 16 g/mol
Moles of methane gas = 0.649 moles
Putting values in equation 1, we get:
Hence, the mass of methane gas produced will be 10.384 g.