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Rom4ik [11]
3 years ago
15

Problem solving with inequalities

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

Option D:

15c ≤ 200

Solution:

Let c be the number of cases of tea bags.

Cost of each tea bag = 15 gold coins

Total gold coins Mad have = 200

<u>Set up an inequality:</u>

Cost of c tea bags = 15 × c = 15c

Mad can buy tea bags at most 200 gold coins.

(At most 200 means 200 is the greater value)

15 × c ≤ 200

15c ≤ 200

Hence option D is the correct answer.

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3 years ago
Please give me the correct answer ​
Ganezh [65]

Answer:

PQ = 5 units

QR = 8 units

Step-by-step explanation:

Given

P(-3, 3)

Q(2, 3)

R(2, -5)

To determine

The length of the segment PQ

The length of the segment QR

Determining the length of the segment PQ

From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.

so

P(-3, 3), Q(2, 3)

PQ = 2 - (-3)

PQ = 2+3

PQ = 5 units

Therefore, the length of the segment PQ = 5 units

Determining the length of the segment QR

Q(2, 3), R(2, -5)

(x₁, y₁) = (2, 3)

(x₂, y₂) = (2, -5)

The length between the segment QR is:

l=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(2-2\right)^2+\left(-5-3\right)^2}

  =\sqrt{0+8^2}

  =\sqrt{8^2}

Apply radical rule: \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

  =8

Therefore, the length between the segment QR is: 8 units

Summary:

PQ = 5 units

QR = 8 units

8 0
2 years ago
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