Answer:
12 dark chocolates
Step-by-step explanation:
Let there are 2x milk chocolates and 3x dark chocolates.
Total no of milk chocolates = 8
ATQ,
2x = 8
x = 4
Dark chocolates = 3x
= 3(4)
= 12
Hence, there are 12 dark chocolates.
You answer would be Oy= 7x-1. I hope this helps!
Answer:
a)
, b)
, c)
, d) ![m(300) \approx 8.842\,g](https://tex.z-dn.net/?f=m%28300%29%20%5Capprox%208.842%5C%2Cg)
Step-by-step explanation:
a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:
![\frac{dm}{dt} = -k\cdot m](https://tex.z-dn.net/?f=%5Cfrac%7Bdm%7D%7Bdt%7D%20%3D%20-k%5Ccdot%20m)
b) The general solution is found after separating variables and integrating each sides:
![m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }](https://tex.z-dn.net/?f=m%28t%29%20%3D%20m_%7Bo%7D%5Ccdot%20e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%20%7D)
Where
is the time constant and ![k = \frac{1}{\tau}](https://tex.z-dn.net/?f=k%20%3D%20%5Cfrac%7B1%7D%7B%5Ctau%7D)
c) The time constant is:
![\tau = \frac{1690\,yr}{\ln 2}](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%5Cfrac%7B1690%5C%2Cyr%7D%7B%5Cln%202%7D)
![\tau = 2438.155\,yr](https://tex.z-dn.net/?f=%5Ctau%20%3D%202438.155%5C%2Cyr)
The particular solution of the differential equation is:
![m(t) = 10\cdot e^{-\frac{t}{2438.155} }](https://tex.z-dn.net/?f=m%28t%29%20%3D%2010%5Ccdot%20e%5E%7B-%5Cfrac%7Bt%7D%7B2438.155%7D%20%7D)
d) The amount of radium after 300 years is:
![m(300) \approx 8.842\,g](https://tex.z-dn.net/?f=m%28300%29%20%5Capprox%208.842%5C%2Cg)
Answer: Its B
Step-by-step explanation: trust me i had this test