4 The temperature at the center of the sun is 1.55 x 10' K. Express this in degrees

Divers in acapulco, mexico, dive headfirst at 8 feet per second from the top of a cliff 87 feet above the pacific ocean. during

xxMikexx [17]

Depends on the wieght of his genitals.

8 0

3 years ago

A 6 V battery is connected to a 24 ohm resistor to create a circuit. The 6 V battery is then replaced with a 12 V battery. How d

11Alexandr11 [23.1K]

Answer:

1.) The current is doubled

2.) moving a magnet up and down near the wire

3.) An electric current in the wire produces a magnetic field.

4.) Distance between Particles (m)

Explanation:

1.) When 6 V battery is connected to a 24 ohm resistor to create a circuit, using ohms law, V = IR

Current I = 6/24 = 0.25 A

When the The 6 V battery is replaced with a 12 V battery,

Current I = 12/24 = 0.5 A

Therefore, The current is doubled

2.) Electric current will be induced when moving a magnet up and down near the wire

3.) An electric current in the wire produces a magnetic field.

4.) Distance between Particles (m)

The force of attraction between two different masses is inversely proportional to the square of the distance between them.

6 0

3 years ago

At the surface of Jupiter's moon Io, the acceleration due to gravity is 1.81 m/s2 . A watermelon has a weight of 40.0 N at the s

Mumz [18]

Answer

acceleration due to gravity on Jupiter's moon,g' = 1.81 m/s²

weight of water melon on earth, W = 40 N

acceleration due to gravity on earth, g = 9.8 m/s²

a) Mass on the earth surface

$M = \dfrac{W}{g}$

$M = \dfrac{40}{9.8}$

M = 4.08 Kg

b) Mass on the surface of Lo

Mass of an object remain same.

Hence, mass of object at the surface of Lo = 4.08 Kg.

c) Weight at the surface of Lo

W' = m g'

W' =4.08 x 1.81

W' = 7.38 N

8 0

3 years ago

An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the len

worty [1.4K]

Answer:

2.74

Explanation:

Magnification = image distance/object distance

Mag = v/u

Given

v = 46cm

u = 16.8

Magnification = 46/16.8

Magnification = 2.74

Hence the magnification is 2.74

7 0

3 years ago

A 27 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 6.1 m/s just before hitting the ground.

Nadusha1986 [10]

<h2>Thus the force of friction is 235 N</h2>

Explanation:

When the bear was at the height of 14 m . Its potential energy = m g h

here m is the mass of bear , g is acceleration due to gravity and h is the height .

Thus P.E = 27 x 10 x 14 = 3780 J

The K.E of the bear just before hitting = $\frac{1}{2}$ m v²

= $\frac{1}{2}$ x 27 x ( 6.1 )² = 490 J

The force of friction f = P.E - K.E = 3290 J

Because the work done = Force x Distance

Thus frictional force = $\frac{3290}{14}$ = 235 N

3 0

3 years ago