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jonny [76]
2 years ago
11

Objects a and b each have a mass of 25 kilograms. object a has a velocity of 5.98 meters/second. object b is stationary. they un

dergo a perfectly elastic collision in one dimension. what is the total kinetic energy of the system after the collision?
Physics
1 answer:
mash [69]2 years ago
7 0

The total kinetic energy of the system after collision is 223.5J

In elastic collision kinetic energy and momentum are conserved.

According to the question

               mass of object a = 25kg

               mass of object b =  25 kg

        initial velocity of a u1 = 5.98 m/s

        initial velocity  of b u2 = 0

so from momentum conservation-

       mau1 + mbu2 = (m1+m2)v

       25kg × 5.98m/s + 25×0 = (25+25)v

              v = 2.99 m/s

Now the total kinetic energy after the collision will be:

          final kinetic energy = 1/2 (m1+m2) v²

                                           = 1/2 (25+25)× (2.99)²

                                           = 223.5 J

    Thus, total kinetic energy of the system after collision is 223.5J

Learn more about elastic collision here:

  brainly.com/question/1808045

    #SPJ4

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Zoe finds that the temperature of a substance is 12 degrees Celsius. What does this tell Zoe about the substance?
maks197457 [2]
Given the temperature, we can tell if the substance is cold or not relative to the reference temperature. For example, compared to the substance having a temperature of 15 degrees C, the substance is colder and it is hotter from the substance of temperature lesser than 12 degrees C. 
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A 3.5 kg block slides along a frictionless horizontal with a speed of 2.5 m/s. After sliding a distance of 5 m, the block makes
Andru [333]

Answer:

  L = 0.416 m

Explanation:

In this exercise to calculate the distance traveled in the branch that climbs the block we can use the concepts of energy

Starting point Flat part

       Em₀ = K = ½ m v²

Final point. Highest part of the ramp

       Em_{f} = U = m g h

As there is no friction the mechanical energy is conserved

        Em₀ =  Em_{f}

        ½ m v² = m g h

       h = v² / 2g

       h = 2.5 2/2 9.8

       h = 0.3189 m

The distance traveled can be found with trigonometry

      sin 50 = h / L

      L = h / sin 50

      L = 0.3189 / sin50

      L = 0.416 m

3 0
4 years ago
What is an apparent change in the frequency of sound or light waves known as?
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The apparent change is the Doppler shift
4 0
4 years ago
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A gamma-ray photon produces an electron and a positron, each with a kinetic energy of 261 keV . h=6.626×10−34J⋅s, c=2.998×108m/s
ddd [48]

Answer:

The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

Explanation:

Given that,

Kinetic energy = 261 KeV

Planck's constant h = 6.626\times10^{−34}\ J.s

Speed of light c=2.998\times10^{8}\ m/s

Mass of electron m_{e}=9.109\times10^{-31}\ kg

Charge q=1.602\times10^{-19}\ C

(A). We need to calculate the energy of the photon

Using formula of rest mass energy

E=m_{0}c^2

E=9.109\times10^{-31}\times(3\times10^{8})^2

E=8.198\times10^{-14}\ J

Energy in eV

E=\dfrac{8.198\times10^{-14}}{1.6\times10^{-19}}

E=512375\ eV

E=0.512\ MeV

The total energy of photon

TE=2(E+K.E)

TE=2(0.512+0.261)

TE=1.546\ MeV

(B). We need to calculate the wavelength of the photon

Using formula of wavelength

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.626\times10^{−34}\times3\times10^{8}}{1.546\times10^{6}\times1.6\times10^{-19}}

\lambda=8.036\times10^{-13}\ m

Hence, The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

7 0
3 years ago
Kyle lays a mirror flat on the floor and aims a laser at the mirror. The laser beam reflects off the mirror and strikes an adjac
fgiga [73]

Answer:

θr = 55.2 °

Explanation:

The law of reflection states that the angle of incidence and the angles of reflection is the same.

Let's use trigonometry to find the angle between the reflected ray, where the horizontal distance x = 55.9 cm and the vertical distance is y = 38.9 cm

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This angle is measured with respect to the x-axis (horizontal), but in general the angles in optics are measured from the y-axis so that the angle is

    θ = 90 - 34.8

    θr = 55.2 °

6 0
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