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Marta_Voda [28]
3 years ago
15

Does anyone know these answers? 50 pts to you if u do.....don't steal from me.

Mathematics
2 answers:
MArishka [77]3 years ago
6 0

Answer:

y = -2x + 3

y = -x + 10

y = 4x + 10

y = 3/2x - 2

y = -1/2x - 1

y = x + 5

y = 25x + 5

y = .99x + 1.99

y = x - 2

y = -1.50 + 1.50

y = 42x + 27

y = -1/3x - 2

*answering for 2nd time because my first got deleted.  eek.

snow_lady [41]3 years ago
3 0

y = -2x + 3

y = -x + 10

y = 4x + 10

y = 3/2x - 2

y = -1/2x - 1

y = x + 5

y = 25x + 5

y = .99x + 1.99

y = x - 2

y = -1.50 + 1.50

y = 42x + 27

y = -1/3x - 2

now i am in my phone can see the photo

sometimes in the computer don't appear the picture

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Answer:

x=1+\sqrt{3} and x=1-\sqrt{3}

Step-by-step explanation:

We have been given the parabola with vertex (1, -9) and y intercept at (0, -6).

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y=a\left(x-h\right)^2+k

Vertex for this formula is given by (h,k)

Compare that with given vertex (1,-9), we get: h=1, k=-9

So plug these into vertex formula:

y=a\left(x-1\right)^2-9...(i)

Plug given point (0, -6). into (i)

-6=a\left(0-1\right)^2-9

-6=a\left(-1\right)^2-9

-6=a\left(1\right)-9

-6+9=a

3=a

Plug a=3 into (i)

y=3\left(x-1\right)^2-9

Now to find x-intercept, we just plug y=0 and solve for x

y=3\left(x-1\right)^2-9

0=3\left(x-1\right)^2-9

9=3\left(x-1\right)^2

3=\left(x-1\right)^2

\pm \sqrt{3}=x-1

1+\pm \sqrt{3}=x

Hence final answer are

x=1+\sqrt{3} and x=1-\sqrt{3}

4 0
3 years ago
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