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3 years ago

PLEASE HURRY!!

Mathematics

2 answers:

notka56 [123]3 years ago

7 0

Answer:

The correct answer is (it is linear)

Step-by-step explanation:

barxatty [35]3 years ago

3 0

Answer: Is a function

the question unfinished so it will be hard to solve

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What is the mean of 4,6,7,7,11,12,15,18,20

ExtremeBDS [4]

Answer:

Step-by-step explanation:

4+6+7+7+11+12+15+18+20= 100

divide by the number of values we have. we have 9 values

100/9=11.1111111111

I hope this helped

4 0

3 years ago

Read 2 more answers

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

2 years ago

Juan baked 250 cookies in 2 hours, How many cookies can he make in 1 minute?

dybincka [34]

Answer:

I would say 2 because the decimal I came out with was 2.09

Step-by-step explanation:

8 0

2 years ago

Please i need your help...Thanks

pishuonlain [190]

Lol I’m not sure but I’m logging in so it’s making me “answer”

8 0

3 years ago

Can anyone help me out with question 6. ASAP prefer teachers but if you know let me know thx!

SVETLANKA909090 [29]

You can take in x values starting from -4 to 4. Substitute the x values in the equation and find the y values.

Using the values, you can plot the line.

Easy :)

7 0

3 years ago