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2 years ago

PLEASE HURRY!!

Mathematics

2 answers:

notka56 [123]2 years ago

7 0

Answer:

The correct answer is (it is linear)

Step-by-step explanation:

barxatty [35]2 years ago

3 0

Answer: Is a function

the question unfinished so it will be hard to solve

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Use the area of a rectangle and the Distributive Property to find each product. 9 X 34

OLga [1]

Answer:

Step-by-step explanation:

Write 34 in tens and units.

34 = 30 + 4

9(30 + 4)

9 * 30 = 270

9* 4 = 36

270 + 36 = 306

After awhile if your practice enough, you can do them in your head.

5 0

2 years ago

Solve the system of linear equations by elimination. -3.x – 5y = -7 -4x + 5y = 14

julia-pushkina [17]

Answer:

(- 1, 2 )

Step-by-step explanation:

Given the 2 equations

- 3x - 5y = - 7 → (1)

- 4x + 5y = 14 → (2)

Add the 2 equations term by term to eliminate y , that is

- 7x + 0 = 7

- 7x = 7 ( divide both sides by - 7 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (1)

- 3(- 1) - 5y = - 7

3 - 5y = - 7 ( subtract 3 from both sides )

- 5y = - 10 ( divide both sides by - 5 )

y = 2

solution is (- 1, 2 )

8 0

2 years ago

Read 2 more answers

Help me please, I need help I don’t understand this problem

jarptica [38.1K]

The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.

Step-by-step explanation:

The equation for the maximum speed, s is given by s²= (16/9)x
where, x is the length of the water line in feet.

It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.

The question is asked to find the maximum speed when the length of the water is 30 feet.

Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.

Now, calculating the maximum speed :

s² = (16/9)(30)

s² = 480 / 9

s² = 53.3

Taking square root on both sides,

s = √53.3

s = 7.3

The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.

6 0

3 years ago

Which posulate proves the two triangles are congruent?

san4es73 [151]

Answer:

D ASA

Step-by-step explanation:

ASA

5 0

2 years ago

Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

5 0

2 years ago