Which symbol is at the beginning and end of a multiline comment block? ### &&& %%% """

Computers and Technology

1 answer:

Aleks04 [339]2 years ago

3 0

Answer:

A multiline block statement uses symbol "/*", "*/ " at the beginning and end respectively.

Explanation:

At the beginning of a multiline block comment /* symbol is used.

At the end of a multiline block comment */ symbol is used.

Thus, a multiline block statement uses symbol "/*", "*/ " at the beginning and end respectively.

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When someone registers a domain name that is a company's trademark, hoping to resell it to the company at an exorbitant profit,

zysi [14]

Answer:

2. testing cybersquatting

Explanation:

Phishing is the fraudulent attempt to obtain sensitive information such as usernames, passwords and credit card details by disguising oneself as a trustworthy entity in an electronic communication. In this case, phishing domain refer to a domain that is not a trustworthy one but try to deceive user into using it in place of the genuine domain.

Cybersquatting also known as domain squatting is registering, selling or using a domain name with the intent of profiting from the goodwill of someone else's trademark. It generally refers to the practice of buying up domain names that use the names of existing businesses with the intent to sell the names for a profit to those businesses.

Identity theft is the illegal use of someone else's personal information in order to obtain money or credit. It is the deliberate use of someone else's identity, usually as a method to gain a financial advantage or obtain credit and other benefits in the other person's name, and perhaps to the other person's disadvantage or loss.

From the above definition, it is seen that someone registering a domain name that is a company's trademark, hoping to resell it to the company at an exorbitant profit is called testing cybersquatting.

3 0

3 years ago

Read 2 more answers

If 209g of ethanol are used up in a combustion process, calculator the volume of oxygen used for the combustion at stp

SOVA2 [1]

Answer:

a) The volume of oxygen used for combustion at STP is approximately 305 dm³

b) The volume of gas released during combustion at STP is approximately 508 dm³

Explanation:

The given chemical reaction equation for the burning of ethanol in air, is presented as follows;

2CH₃CH₂OH (l) + 6O₂ (g) → 4CO₂ (g) + 6H₂O

The mass of ethanol used up in the combustion process, m = 209 g

The molar mass of ethanol, MM = 46.06844 g/mol∴

The number of moles of ethanol in the reaction, n = m/MM

∴ n = 209 g/(46.06844 g/mol) ≈ 4.537 moles

a) Given that 2 moles of ethanol, CH₃CH₂OH reacts with 6 moles of oxygen gas molecules, O₂, 4.54 moles of ethanol will react with (6/2) × 4.537 = 13.611 moles of oxygen

The volume occupied by one mole os gas at STP = 22.4 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, 'V', is given as follows;

V = 13.611 mol × 22.4 dm³/mole = 304.8864 dm³ ≈ 305 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, V = The volume of oxygen used for the combustion ≈ 305 dm³

b) The total number of moles of gases released in the reaction, is given as follows;

The total number of moles = (4.537/2) × (4 + 6) = 22.685 moles of gas

The total volume of gas released, $V_T$ = The volume of gas released during the combustion at STP = 22.685 moles × 22.4 dm³/mole = 508.144 dm³ ≈ 508 dm³