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Mariana [72]
3 years ago
14

Which symbol is at the beginning and end of a multiline comment block? ### &&& %%% """

Computers and Technology
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

A multiline block statement uses symbol "/*",  "*/ " at the beginning and end respectively.

Explanation:

At the beginning of a multiline block comment /* symbol is used.

At the end of a multiline block comment  */  symbol is used.

Thus, a multiline block statement uses symbol "/*",  "*/ " at the beginning and end respectively.

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Designers are comparing performance between a multi-core processor equipped with 16 in-order cores and a dual-core superscalar p
Nataly [62]

Explanation:

it will be k because it process faster an it comsume less elecricity

5 0
2 years ago
The enhanced for statement allows you to iterate through the elements of an array or a collection without using a counter. Give
lesya [120]

Answer:

Check the explanation

Explanation:

public class EnhancedForExample {

   public static void main(String[] args) {

       int[] arr = {4, 2, 9, 1, 5, 7};

       for(int num : arr) {

           System.out.println(num);

       }

   }

}

Kindly check the attached image below for the code output.

7 0
3 years ago
Read 2 more answers
circular_prime A number is called a circular prime if all rotations of its digits form a prime. For example, the number 197 is a
Lilit [14]

Answer:

function out=circular_primes(no)

prim=primes(no);% find the all prime number till the given number

pr=0;

nos=[];

po=[];

for p=1:length(prim)

   n=prim(p); % picking up each prime no one by one

   n=num2str(n);% change into string for rotation of no

   d=length(n); % length of string

   if d>1          % take nos greater than 10 beacuase below 10 no need for rotation

       for h=1:d

           a=n(1);

           for r=1:d % for rotation right to left

               if r==d  5 % for the last element of string

                   n(d)=a;

               else

               n(r)=n(r+1); %shifting

               end

           end

           

       s=str2num(n); % string to number

       nos=[nos,s]; % store rotated elements in array

       end

       if nos(end)==no   %if given no is also a circular prime we need smaller

           break;

       end

       for gr=1:length(nos) % checking rotated nos are prime or not

           p1=isprime(nos(gr));

           po=[po,p1];    %storing logical result in array

       end

           if sum(po(:))==length(nos) %if all are prime the length and sum are must be equal

               

               pr=pr+1;

               out=pr;

           else

               out=pr;

           end

       po=[];

       nos=[];

   else  

       s=str2num(n); %numbers less than 10

       f=isprime(s);

       if f==1

           pr=pr+1;

           out=pr;

       else

           out=pr;

       end

   end

       

      end

end

Explanation:

3 0
3 years ago
High quality pages in a task should all get the same Needs Met rating. For example, a high quality page for a common interpretat
miskamm [114]

Answer:

The given statement is False.

Explanation:

  • Needs Met Rating of a result show us that how much the result is fulfilling the query of the user. The greater the needs met rating is, the greater the satisfaction of the user is.
  • If a page has high quality then it can or can not be useful for the user.
  • If the page has high quality as well as high needs met rating then it is best for the user.
  • If the page has high quality and has low needs met rating that means it is not relevant to the query so not useful for the user.
  • Thus, it is concluded that high quality pages in a task shouldn't all get the same needs met rating rating rather need met rating is dependent upon the relevancy and usefulness of the result to the need and query of the user.
8 0
3 years ago
Design and implement a program to display each directory entry information (files and directories) of current directory, and wit
FromTheMoon [43]

Answer: The code below can display directory as stated in the question

Explanation:

char *

gnu_getcwd ()

{

 size_t size = 100;

 while (1)

   {

     char *buffer = (char *) xmalloc (size);

     if (getcwd (buffer, size) == buffer)

return buffer;

     free (buffer);

     if (errno != ERANGE)

       return 0;

     size *= 2;

   }

}

3 0
3 years ago
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