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2 years ago

WILL MARK BRAINLIEST HELP

Computers and Technology

2 answers:

Katarina [22]2 years ago

4 0

Answer:

One drawback of transferring RAW files directly to his computer to save and share them is that the photos have a much larger file size than JPG files ( A )

Explanation:

Raw format of pictures keeps the original characteristics of the picture such as the contrast and the sharpness of the pictures without compression or processing . The raw file format is larger than the JPG file format because in the JPG file format the pictures undergo some sort of compression and formatting.

Smaller file sizes are easier to share and transfer, hence the disadvantage to Miguel using the raw format is the difficulty in transferring he file to his computer and also sharing it.

using RAW doesn't make picture look smaller in anyway.

hichkok12 [17]2 years ago

3 0

My guess would be A.

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Write a program that initializes a string variable and prints the first three characters, followed by three periods, and then th

d1i1m1o1n [39]

firstly we have to initialize the variable, means to give variable a value and then print the statement

string = "fahadisahadam"

print(string[:3]+"..."+string[-3:])

string is a data type that contains two or more characters.

means the string is fahadisahadam so the print will print first three characters. follow by three periods(...) and then last three characters.

The output will be:

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3 years ago

Write a complete Java program called Rooter that gets a positive integer called "start" from the user at the command line and th

Nataly_w [17]

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Rooter{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int start;

System.out.print("Start: ");

start = input.nextInt();

while(start<=0){

System.out.print("Number must be positive\nStart: ");

start = input.nextInt(); }

while(start>=0){

System.out.println(Math.sqrt(start));

start--; }

}

Explanation:

This declares start as integer

int start;

This prompts the user for input

System.out.print("Start: ");

This gets input for start

start = input.nextInt();

The following is repeated until the user input is valid i.e. positive

while(start<=0){

System.out.print("Number must be positive\nStart: ");

start = input.nextInt(); }

The following while loop prints the square root of each number till 0

while(start>=0){

System.out.println(Math.sqrt(start));

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2 years ago

1. Which of the following statements is true regarding the use of refrigerants?

kondaur [170]

A) Records of the dates and quantities of refrigerant recovered and recycled are unnecessary

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3 years ago

Read 2 more answers

Technician A says that oil for the rod bearings comes from splash off the crankshaft. Technician B says that lubrication to the

worty [1.4K]

Answer: technician B

Explanation:

The oil is picked up from the oil pump though a pick up tube that is mounted on the oil pump. The end of the pick up tube sits in the oil at the bottom of the oil pan. The oil is then forced through holes that are drilled into the block. Those holes which are called (journals) lead to the main bearings,rod bearings,lifters, camshaft, ect..

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2 years ago

Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th

ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112 ≈ 7/4

fractional value ( F ) = 0.112

And, numeric value of the quantity ( V ) = 7

The exponent bits will be represented as : 100----01.

while The fraction bits will be represented as : 1100---0.

B) The largest odd integer that can be represented exactly

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

= 1.11------12 = 2 - 2-n

also the fractional value ( F ) =

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits will be represented as follows: n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

C) The reciprocal of the smallest positive normalized value

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E ) = 2k-1 – 2

While the significand value ( M ) = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0

2 years ago