Answer:
6.76 mol/L
Explanation:
<em>A chemist prepares a solution 0.607 kg of calcium bromide by measuring out of calcium bromide into a 450. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's calcium bromide solution. Be sure your answer has the correct number of significant digits.</em>
Step 1: Given data
- Mass of calcium bromide (solute): 0.607 kg (607 g)
- Volume of solution (V): 450. mL
Step 2: Calculate the moles of solute
The molar mass of calcium bromide is 199.89 g/mol.
607 g × 1 mol/199.89 g = 3.04 mol
Step 3: Convert "V" to liters
We will use the conversion factor 1 L = 1000 mL.
450. mL × 1 L/1000 mL = 0.450 L
Step 4: Calculate the concentration of calcium bromide in mol/L
[CaBr₂] = 3.04 mol/0.450 L = 6.76 mol/L
