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Galina-37 [17]
3 years ago
10

A cough syrup contains 5.0 % ethyl alcohol C2H5Oh by mass. If the density of the solution is 0.9928 g/ml. Determine the molarity

of the alcohol in the cough syrup.
Chemistry
1 answer:
Nostrana [21]3 years ago
6 0

<u>Answer:</u> The molarity of ethyl alcohol in cough syrup is 1.08 M

<u>Explanation:</u>

We are given:

(m/m) of ethyl alcohol = 5.0 %

This means that 5 g of ethyl alcohol is present in 100 g of solution.

To calculate volume of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 0.9928 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

0.9928g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=100.725mL

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Mass of solute (ethyl alcohol) = 5 g

Molar mass of ethyl alcohol = 46.07 g/mol

Volume of solution = 100.725 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{5g\times 1000}{46.07g/mol\times 100.725mL}\\\\\text{Molarity of solution}=1.08M

Hence, the molarity of ethyl alcohol in cough syrup is 1.08 M

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CH4= 12 g/mol +1(4) g/mol = 16 g/mol

With 0.893 mol sample, its corresponding mass is

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D. MgO + 2HCI – MgCl2 + H20

<h3>Further explanation</h3>

The chemical equation is said to be balanced if the number of atoms in the reactants is equal to the number of atoms in the product

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How long does it take electrons to get from the car battery to the starting motor? Assume the current is 137 A and the electrons
WARRIOR [948]

Answer:

t = 55.79 min

Explanation:

First, the problem is asking for calculate the time that it takes electrons from the battery to the motor.

The general formula to calculate time is:

<em>t = d/V (1)</em>

Where:

d: distance or length

V: speed

Now, we don't have data of speed, but we can know an expression of current density in function of the distance which is the following:

<em>J = n*q*V (2)</em>

Where:

q: charge of the particle (1.6x10^-19 C)

n: number of charge carriers per unit of volume

Current density (J) is actually current per Area so:

<em>J = I/A (3)</em>

Replacing (3) in (2) we have:

I/A = nqV

Solving for V:

<em>V = I/Anq (4)</em>

Finally, if we replace this expression in (1) we have:

<em>t = nqAd / I (5)</em>

Now, the value of n, it's not given but it can be calculated because we have mass density, molar mass and avogadro's number, so this value of "n" can be calculated using the following expression:

<em>n = D * Av / MM (6)</em>

Where:

D: mass density (kg/m³)

Av: avogadro number (6.02x10^23 atom/mol)

MM: molar mass (kg/mol)

Putting the data that we know to calculate n we have:

n = 8960 * 6.02x10^23 / 0.0635

n = 8.49x10^28 atom/m³

Now with the value of n, we can finally calculate the time:

<em>t = nqAd / I </em>

A is the area and it should be in m²: 44.6 mm² / 1x10^6 m = 4.46x10^-5 m²

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t = 8.49x10^28 * 1.6x10^-19 * 4.46x10^-5 * 0.757 / 137

t = 3,347.63 s

But the answer is in minute so:

t = 3,347.63 / 60

<em>t = 55.79 min</em>

so the electrons takes 56 min aprox. to go from the car battery to the starting motor.

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