Question

Please help with all 3 parts!

Answer 1

Answer:

1:Part A.

$\bold{42.2 g C_{12}H_{22}O_{11} \:in \:528 g H₂O}$

Mass Percent=$\bold{\frac{Mass\: of \:Solute}{Mass\: of \:Solution}×100\%}$

=$\frac{42.2}{528}*100\%=\bold{\underline{7.99\: or \:8\%}}$

Part B.

$\bold{198\:m g\: C_{6}H_{12}O_{6} \:in\:4.71 g\: H₂O}$

mass of solute: 198mg

mass of solvent :4.71g=4710g

Mass Percent=$\bold{\frac{Mass\: of \:Solute}{Mass\: of \:Solution}×100\%}$

=$\frac{198}{4710}*100\%=\bold{\underline{4.20\%}}$

Part C.

$\bold{8.85 g NaCl \:in \:190 g\: H₂O}$

Mass Percent=$\bold{\frac{Mass\: of \:Solute}{Mass\: of \:Solution}×100\%}$

=$\frac{8.85}{190}*100\%=\bold{\underline{4.66\%}}$

Answer 2

Answer:

It will help you !!!!!!!!!!