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horsena [70]
3 years ago
7

Can anyone help me with these 2 please ! I’ll mark you as a brainliest.

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

i dont see a question?

Step-by-step explanation:

You might be interested in
A 90-kg astronaut biologist searches for microbial life on Mars where the gravitational acceleration is g = 3.71 m/s2. What is t
Yuki888 [10]
M = 90 kg,
On Mars:  g = 3.71 m/s² 
Weight = m · g = 90 kg · 3.71 m/s² = 333.9 N
1 N = 0.2248 lbf
333.9 · 0.2248 = 75.06072 lbf ≈ 75 lbf
5 0
3 years ago
Please find it <br>please help ​
Sedbober [7]

Answer:

29/30

Step-by-step explanation:

11/12 + 1/20

220+12/240

232/240 ........divide it by 8

29/30

6 0
2 years ago
There is a cereal box and the dimensions are 10 inches tall, 3 inches wide and 7 inches long. If you were to fill the box with c
JulsSmile [24]

Answer:

$6.30

Step-by-step explanation:

First, get the volume of the cereal box with the equation V = lwh.

V = 7(3)(10) = 210 cubic inches

Since it costs $.03 per cubic inch, multiply this cost by the volume to get the total cost to fill the box.

.03(210) = $6.30

6 0
2 years ago
"Lito had some marbles. He gave ½ of his marbles plus 1 to Felix, ½ of the remaining marbles plus 1 to Ces, and ½ of the last re
Nuetrik [128]

let

x-------> total amount of marbles at the beginning


we know that

1) He gave ½ of his marbles plus 1 to Felix

(1/2)*x+1=(x+2)/2 (Felix's marbles)

remaining=x-[(x+2)/2]-----> [2x-x-2]/2------> (x-2)/2


2)½ of the remaining marbles plus 1 to Ces

(1/2)*[(x-2)/2]+1=[(x-2)/4]+1-----> (x+2)/4 (Ce's marbles)

remaining=[(x-2)/2]-[(x+2)/4]-----> [2x-4-x-2]/4------> (x-6)/4


3) ½ of the last remaining marbles plus 1 to Pedro

(1/2)*[ (x-6)/4]+1=[(x-6)/8)+1------> (x+2)/8 (Pedro's marbles)

remaining=[(x-6)/4]-[(x+2)/8]------> [2x-12-x-2]/8-----> (x-14)/8


4)If Lito had 1 marble left for himself

so

the last remaining is equal to 1

(x-14)/8=1-----> x-14=8------> x=22 marbles


Verify

(x+2)/2 (Felix's marbles)------> (22+2)/2=12

(x+2)/4 (Ce's marbles)------> (22+2)/4=6

(x+2)/8 (Pedro's marbles)---> (22+2)/8=3

Lito's marbles------------------> 1

total=12+6+3+1=22--------> is ok


therefore


the answer is

the total amount of marbles at the beginning was 22

4 0
3 years ago
How many integers between 10 and 500 begin and end in 3?
hodyreva [135]

If from 0 - 10 there is 1 number ending in 3 (3) we'll aplly the same logic to 500.

Between 0-10 there is 3. Between 10 - 20 there is 13. Between 20-30 there is 23. Between 30-40 there is 33, etc.


If we divide 500 into 10 we get 50:

500 / 10 = 50


That means there are 50 groups of 10 in the number 500. If we know that every 10 numbers has 1 ending in 3, we multiply 1 by 50:

1 x 50 = 50

So, our conclusion is, that there are 50 numbers ending in 3 between 10 and 500.


Hope it helped,


BioTeacher101

5 0
3 years ago
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