Answer:
x²+6x+9=0
x²+3x+3x+9=0
x(x+3)+3(x+3)=0
(x+3)(x+3)=0
either
x+3=0
x=-3
or
x+3=0
x=-3
Step-by-step explanation:
next method
x²+6x+9=0
x²+2×x×3+3²=0
it is in formula of (x+y)²
(x+3)²=0
x+3=√0
x+3=0
x=-3
Answer:
8) 10°
9) X can not be determined.
10) 10°
11) 12 units.
Step-by-step explanation:
8) The three sides of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each angle will be 60°.
So, 6x = 60°
⇒ x = 10°.
9) The three angles of the given triangle are equal. Hence, the triangle is an equilateral triangle, hence each side will be equal.
So, 6x - 5 = 6x
So, x can not be determined from this equation.
10) Δ KLM is equilateral, so, KN will bisect ∠ MKL. So, ∠ NKL = 30°
Hence, 3x = 30°
⇒ x = 10°
11) In Δ XYZ, XZ = XY , so, ∠ Z = ∠ Y.
Again, ∠ X is given to be 60°.
Therefore, each angle is 60°.
So, the triangle XYZ is equilateral, and each side will be equal.
So, 3x + 8 = 4x - 4
⇒ x = 12 units. (Answer)
( 30 / 100 ) * (15.40 ) = ( 3 / 10 )* (15.40) = 36.20 / 10 = 3.62$.
Answer:
The team can assign field positions to 9 of the 19 players in 181,440 different ways.
Step-by-step explanation:
Since the outfielders (left field, center field, right field) can play any outfield position, the infielders (1st base, 2nd base, 3rd base, short stop) can play any infield position, the pitchers can only pitch, and the catchers can only catch, supposing a certain team has 20 players, of whom 3 are catchers, 4 are outfielders, 6 are infielders, and 7 are pitchers, to determine how many ways can the team assign field positions to 9 of the 19 players, putting each of the 9 selected players in a position he can play, and ensuring that all 9 field positions are filled, the following calculation must be performed:
3 x 7 x 6 x 5 x 4 x 3 x 4 x 3 x 2 = X
21 x 30 x 12 x 24 = X
630 x 12 x 24 = X
181,440 = X
Therefore, the team can assign field positions to 9 of the 19 players in 181,440 different ways.
