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3 years ago

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Mathematics

1 answer:

Ivanshal [37]3 years ago

8 0

Answer: The only answer is A.

Step-by-step explanation:

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PLEASE HELP Which equations could this model represent? Choose all answers that are correct. A. 3 X 2/5= M B.1 2/5 X 3 = m C

Vaselesa [24]

C. and also D. are the answer s

4 0

3 years ago

A car has a 16-gallon fuel tank. When driven on a highway, it has a gas mileage of 30 miles per gallon. The gas mileage (also ca

valkas [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

2.4 + 5.4q – 4.5q + 3.6<br><br> a.6+1.1q<br> b.9.9q+6<br> c.0.9q+6<br> d.9.9q-6

Yuri [45]

You have to add the same kind of terms, in this case the ones that have a variable (5.4q and -4.5q) and the ones that don't (2.4 and 3.6), like this:

(5.4q - 4.5q) + (2.4 + 3.6) = 0.9q + 6

The answer is c. 0.9 +6

8 0

3 years ago

Kristen and melissa spent 35% of their $32 on movie tickets. how much money did they spend

Ostrovityanka [42]

Answer:

11.2$

Step-by-step explanation:

Kristina and Melissa had 32$ at total

● 32$ => 100%

They have spent 35%

Let x be that amount

● x => 35%

●32 => 100

● x => 35

● x = (35×32)/100 = 11.2$

They have spent 11.2$

3 0

3 years ago

Read 2 more answers

Total blood cholesterol level was measured for each of

laiz [17]

<h3>Answer: Mean = 218.9.</h3><h3>Median = 229</h3><h3>Mode = Zero mode.</h3>

Step-by-step explanation:

Given blood cholesterol level was measured for each of 8 adults (in mg/dL) are:

264, 191, 160, 148, 262, 212, 268, 246

In order to find the mean, we need to add all those 8 numbers and divide by 8.

Therefore, mean = $\frac{264+191+160+148+262+212+268+246}{8} =\frac{1751}{8} =218.9.$

In order to find the median, we need to arrange them in ascending order:

148, 160, 191, 212, 246, 262, 264, 268.

The middle most two values are 212 and 246.

Therefore, median = $\frac{212+246}{2} =\frac{458}{2} = 229.$

<h3>Median = 229.</h3>

$\mathrm{The\:mode\:is\:the\:term\:in\:the\:data\:set\:that\:appears\:the\:most.}$

$\mathrm{If\:there\:is\:more\:than\:one\:term\:that\:appears\:the\:most,\:then\:there\:is\:no\:mode.}$

$\mathrm{Count\:the\:number\:of\:times\:each\:element\:appears\:in\:the\:list}$

$\begin{pmatrix}148&160&191&212&246&262&264&268\\ 1&1&1&1&1&1&1&1\end{pmatrix}$

$\mathrm{The\:most\:common\:element\:is\:not\:unique,\:so\:there\:is\:no\:mode}$

<h3>Therefore, Mode = Zero mode.</h3>

5 0

3 years ago

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Help meeeeeeeeeeeeeeeeeeeeee