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2 years ago

Simplify 1/2(6x−10)+5x.

Mathematics

2 answers:

masha68 [24]2 years ago

8 0

The answer for this is 8x+5

Sav [38]2 years ago

6 0

The answer would be 8x -5

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X/3 -6 =y<br><br> Solve for x

Paul [167]

Answer:

x= 3(y+6) or x = 3y + 18

Step-by-step explanation:

get the "x" by itself.

so first +6 on both sides of the equation to make it x/3=y+6

then multiply both sides by 3 to make it x=(y+6)*3

3 0

2 years ago

342,802 to the nearest hundred thousands

Maksim231197 [3]

1. The number 3 is located in the hundred thousands place.

2. Since the number 4 is located in the ten thousands place, it's telling 3 to stay the same

Stays the Same: 1,2,3,4
Goes Up: 5,6,7,8, etc...

342,802 ⇒ 300,000

3 0

3 years ago

Read 2 more answers

A projectile is launched into the air. The function h(t) = –16t2 + 32t + 128 gives the height, h, in feet, of the projectile t s

Zinaida [17]

Answer:

t = 4 seconds

Step-by-step explanation:

The height of the projectile after it is launched is given by the function :

$h(t)=-16t^2+32t+128$

t is time in seconds

We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0

So,

$-16t^2+32t+128=0$

The above is a quadratic equation. It can be solved by the formula as follows :

$t=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}$

Here, a = -16, b = 32 and c = 128

$t=\dfrac{-32\pm \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=\dfrac{-32+ \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}, \dfrac{-32\- \sqrt{(32)^2-4\times (-16)(128)} }{2\times (-16)}\\\\t=-2\ s\ \text{and}\ 4\ s$

Neglecting negative value, the projectile will land after 4 seconds.

4 0

3 years ago

Bob bought a boat for $20.00 and sold it at a loss of $8.00. What was the selling price?

qwelly [4]

he sold it for $12.00

7 0

3 years ago

I don't really understand this question so can someone please help

Makovka662 [10]

Hello,

(5x-2)+(2x+6)=67
==>7x+4=67
==>7x=67-4
==>7x=63
==>x=63/7
==>x=9
|AB|=5x-2=5*9-2=45-2=43 (miles)

8 0

2 years ago