There are four nitrogenous bases that makes DNA. These are A, T, G and C. If a DNA strand has eight pairs of nitrogenous bases, the eight bases can be
1. AA GG TT CC
2. GC GG AT CG
3. AT TA GG GC
4. GA AG GC GG
Like this, there can be 65,536 different sequences with ATCG.
Since we have 4 nitrogenous bases, pairing will make 4 X 4 = 16 combinations. If we have to make 8 pairs of bases, the number of possible sequences would be 4 to the power 8.
Answer: THERE WILL BE 65,536 DIFFERENT SEQUENCES OF 8 BASES.
second option
Explanation:
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Dominant- determines the dominant character, more frequently found in the population, produces the complete polypeptide, does not require the presence of a similar gene, more likely to be inherited, more prone to produce diseases
recessive- responsible for the recessive character, expresses the recessive trait, produces an incomplete polypeptide, requires the presence of a similar gene, less likely to be inherited, less prone to produce disease
Answer:
If a female child has hemophilia it is possible that the mother is a carrier of the hemophilia gene and the father has hemophilia.
Explanation:
- A daughter gets X chromosome from both her parents.
- It is generally seen in males.
- Hemophilia is generally recessive in females.They act as carriers of hemophilia. This occurs because they have a X chromosome that dominates the hemophilia affected gene that they inherit from any parent.
- But, if both the parents have faulty genes ,i.e the mother is the carrier of the gene and the father is hemophiliac, then the chances are the daughter has hemophilia too.
Answer:
<h2>Both Yy</h2>
Explanation:
1. As given here,
Total offspring are= 124;
that produce yellow squash= 93;
that produce green squash= 31;
2. Let Y for yellow producing squash and y for green squash;
Y is dominant over y.
3. Cross between two yellow squash producing plants
Genotype of parents = Yy and Yy
offspring = YY, Yy, Yy and yy,
as Y is dominant over y, so YY and Yy all produce yellow squash, and yy produce green squash.
4. Their phenotypic ratio is 3:1 , as in question 93: 31
