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3 years ago

Circle P below What is the arc measure of major arc ABC in degrees?

Mathematics

2 answers:

Archy [21]3 years ago

7 0

Answer:

measure of arc ABC = 283°

Step-by-step explanation:

First we have to find y

7y - 7 + 4y + 6 +20y - 11 = 360

31y - 12 = 360

31y = 372

y = 12

Since all the angles are central angles and intercepted arcs of those angles have the same measure,

the measure of arc ABC = 4y + 6 + 20y - 11

= 24y - 5

= 24(12) - 5

= 283

Cloud [144]3 years ago

3 0

Answer: 283

Step-by-step explanation:Khan Academy

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A sequence of two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH

Burka [1]

Two transformations that can be used to show that polygon ABCDE is congruent to polygon GFJIH : <u>rotation -90° and translation (0,2)</u>

<h3>Further explanation</h3>

There are several forms of transformation, including translation, dilation, rotation or reflection

There are 2 shapes of geometry:

Similar figures:

the same shape but different in size,

Congruent figures:

the same size and the same shape

Both polygons will appear congruent if, after being transformed, the two polygons will map exactly to each other

A sequence of two transformations e can do is :

1. rotation -90°

Let point H(4,1) from polygon GFJIH , we rotate -90°

$\left[\begin{array}{ccc}x'\\y'\end{array}\right]=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}4-6\\1+1\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}0&1\\-1&0\end{array}\right]\left[\begin{array}{ccc}-2\\2\end{array}\right]+\left[\begin{array}{ccc}6\\-1\end{array}\right]\\\\=\left[\begin{array}{ccc}8\\1\end{array}\right]$

2. translation (0,2)

$\left[\begin{array}{ccc}8\\1\end{array}\right]+\left[\begin{array}{ccc}0\\2\end{array}\right]=\left[\begin{array}{ccc}8\\3\end{array}\right]$

<h3 /><h3>Learn more</h3>

brainly.com/question/13715226

Keywords: transformation, translation, rotation

#LearnWithBrainly

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3 years ago

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Jim Debt was reviewing the total accounts receivable. This month he received $80,000 from Credit customers. This represented 40

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3 years ago

A method for finding the volume of any solid for which cross sections by parallel planes have equal area is called

lapo4ka [179]

The appropriate response is Caliveire's <span>Principle</span> It is a technique, with the recipe given beneath, of finding the volume of any strong for which cross-segments by parallel planes have measured up to ranges. This incorporates, yet is not constrained to, chambers and crystals.

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Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems

Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for $(x_{1},y_{1}) and (x_{2},y_{2})$

Use the distance formula to find the length = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length = $\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\$

length = $\sqrt{80}$

length = 8.94

Use the distance formula to find the width = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width = $\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\$

width = $\sqrt{(-10 )^{2} + (11 )^{2}}\\$

width = $\sqrt{100 + 121}\\$

width = $\sqrt{221}$

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

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3 years ago

Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

$\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}$

Recall that since both lines are parallel, we have that,

$m_1=m_2$

Thus

$m_2\text{ = 1}$

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

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1 year ago