That's an obvious question
Answer:
The answer to the question is
The mass of the water in the container, assuming that all the heat lost by the copper is gained by the water is 116.23 grams
Explanation:
To solve this we list out the variables thus,
mass of copper = 110g
specific heat capacity of copper = 0.20 j/C g
Initial temperature of copper = 82.4 C
Final temperature of copper and water = 24.9 C
therefore
From the formula for sensible heat, ΔH = m×c×ΔT
we have, where
H = senced heat,
m = mass,
ΔT = temperature change
110 × 0.20 × (82.4 - 24.9) = mw × 4.186 × (24.9 - 22.3)
1265 J = mw ×10.8836 or mw = 116.23 g
Therefpre the mass of water is 116.23 g
Answer:
A - Is the material malleable or ductile?
Explanation:
Gay-Lussacs law gives the relationship between pressure and temperature of a gas.
It states that pressure of gas is directly proportional to the temperature at constant volume.
P/T = k
Where k - constant
P1/T1 = P2/T2
Where parameters for the first instance are on the left side and parameters for the second instance on the right side of the equation.
3.74 atm /394 K = P/789 K
P = 7.49 atm