A scientist performs an experiment in which a radium–226 (Ra–226) atom decays into radon–222 (Rn–222). The scientist concludes t
2 answers:
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Explanation:
Assuming that moles of nitrogen present are 0.227 and moles of hydrogen are 0.681. And, initially there are 0.908 moles of gas particles.
This means that, for
moles of + moles of
= 0.908 mol
Since, 2 moles of =
= 0.454 mol
As it is known that the ideal gas equation is PV = nRT
And, as the temperature and volume were kept constant, so we can write
=
=
=
= 5.2 atm
Therefore, we can conclude that the expected pressure after the reaction was completed is 5.2 atm.