Oxygen is participating in non-polar covalent bond(s)
Oxygen forms 2 covalent bond.
This is because oxygen atoms have 6 valence electrons. This means that it has 2 lone pairs and 2 unpaired electrons that are shared in order to achieve octet configuration.
In this chemistry, the 2 lone pairs on the oxygen are not shared with any other atoms. Instead; they are assigned to the oxygen atom. The formal charge on the oxygen atom is zero. Oxygen's atomic number is 8 and is equal to the sum of the number of its valence and inner shell electrons.
<h3>What is non-polar covalent bonding?</h3>
Nonpolar covalent bonding is a kind of covalent bond in which the bonding electrons are shared equally between the two atoms.
Learn more about non-polar covalent bonding:
brainly.com/question/26056508
Answer:
Wave is a disturbance or energy that propagate through medium from one point to other point
So basically it is a flowing energy that flows into the medium and hence medium particles start oscillating about their mean position to and fro.
This motion of medium particles or this to and fro motion is about their mean position and this will always be cyclic or periodic motion
This means the disturbance or energy continuously flow through the medium such that it will change the position of medium particle and this will be cyclic in order
For an example
y(x,t) = Asin(kx - ωt + φ)
So here above equation of wave is a travelling wave in which displacement of medium particle from its mean position is given by "y"
Now we can see that this disturbance depends upon the sine function and it will repeat its same position after every 2 pi time interval as it is cyclic function for this value
Due to this phenomenon of repetition of its same position we can say that it is disturbance of wave is cyclic.
Explanation:
Answer:
it forms nitrogen gas if it reacts with hydrochloric acid.
Answer:
Explanation:
[ AX₂] is decomposing to form products .
Rate of reaction =1/2 x- [ AX₂] / t
rate between 0 to 2 s
- [ AX₂] = change in concentration of AX₂ = .05 - .0448
= .0052 mol/L ,
time t = 2s
1/2 x [- AX₂] / t = 1/2 x .0052 / 2
= .0013 mol/L.s
between 2 to 6 second
- [ AX₂] = .0448 - .0300
=.0148 mol/L
t = 6-2 = 4 s
1/2 x [ -AX₂] / t = 1/2 x .0148 / 4
= .00185 mol/L.s
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Answer: 160.40 g Fe2O3 are needed.
Explanation:
Balanced equation: 2 Al + Fe2O3 —> Al2O3 + 2Fe
54.2 g Al * 1 mol Al / 26.98 g Al * 1 mol Fe2O3 / 2 mol Al * 159.69 g Fe2O3 / 1 mol = 160.40 g Fe2O3 are needed.
