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3 years ago

Explain why magnetic damping might not be effective on an object made of several thin conducting layers separated by insulation.

Physics

1 answer:

andrew-mc [135]3 years ago

7 0

Answer:

The eddy currents will be very small.

Explanation:

An object made of several thin conducting layers separated by insulation may not be affected by magnetic damping because the eddy current produced in each layer due to induction will be very small and the opposing magnetic flux produced by the eddy currents will be very small.

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An object is 25.0 cm from the mirror, its height is 5.0 cm, and focal length is 8.0 cm. What is the distance from the image to t

Oksana_A [137]

1.) Use the formula to solve -
   1/f = 1/do + 1/di; Where f = focal length; 1/do + 1/di
   1/f = 1/do + di
   1/8 = 1/25 + 1/?
   .125 = .04 + 1/di
.125 -.04 = 1/di (transferred .04 to the left side of the equation)
.085/1 = 1/di
.085di/.085 = 1/.085 (multiplied both sides by di and divided both sides by .085)
   di = 11.76 or 12
2.) Therefore, 12 cm is the distance from the image to the mirror

3 0

3 years ago

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The weight of an iron block is 8.0±0.3? and is placed on a wooden base of area, 3.5±0.2? 2. Calculate the pressure exerted by th

vesna_86 [32]

Answer:

Explanation:

Units...Nothing is accurate without UNITS. 8.0±0.3 lbs,? Newtons? 3.5±0.2 m²? ft²? cm²? km²? furlong²? fathoms²?

your answer will be 8.0±0.3 / 3.5±0.2 units / units²

8 0

3 years ago

Three identical resistors are connected in parallel to a battery. If the current of 12. A flows from the battery, how much curre

Doss [256]

Answer:

4 A

Explanation:

We are given that

$R_1=R_2=R_3=4\Omega$

I=12 A

We have to find the current flowing through each resistor.

We know that in parallel combination current flowing through different resistors are different and potential difference across each resistor is same.

Formula :

$\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}$

Using the formula

$\frac{1}{R}=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}=\frac{3}{4}$

$R=\frac{4}{3}\Omega$

$V=IR$

Substitute the values

$V=12\times \frac{4}{3}=16 V$

$I_1=\frac{V}{R_1}=\frac{16}{4}=4 A$

$I_1=I_2=I_3=4 A$

Hence, current flows through any one of the resistors is 4 A.

7 0

3 years ago

A photovoltaic panel of dimension 2 m × 4 m is installed on the roof of a home. The panel is irradiated with a solar flux of GS

Flura [38]

Answer:

(a) the electrical power generated for still summer day is 1013.032 W

(b)the electrical power generated for a breezy winter day is 1270.763 W

Explanation:

Given;

Area of panel = 2 m × 4 m, = 8m²

solar flux GS = 700 W/m²

absorptivity of the panel, αS = 0.83

efficiency of conversion, η = P/αSGSA = 0.553 − 0.001 K⁻¹ Tp

panel emissivity , ε = 0.90

Apply energy balance equation to determine he electrical power generated;

transferred energy + generated energy = 0

(radiation + convection) + generated energy = 0

$[\alpha_sG_s-\epsilon \alpha(T_p^4-T_s^4)]-h(T_p-T_\infty) - \eta \alpha_s G_s = 0$

$[\alpha_sG_s-\epsilon \alpha(T_p^4-T_s^4)]-h(T_p-T_\infty) - (0.553-0.001T_p)\alpha_s G_s$

(a) the electrical power generated for still summer day

$T_s = T_{\infty} = 35 ^oC = 308 \ k$

$[0.83*700-0.9*5.67*10^{-8}(T_p_1^4-308^4)]-10(T_p_1-308) - (0.553-0.001T_p_1)0.83*700 = 0\\\\3798.94-5.103*10^{-8}T_p_1^4 - 9.419T_p_1 = 0\\\\Apply \ \ iteration \ method \ to \ solve \ for \ T_p_1\\\\T_p_1 = 335.05 \ k$

$P = \eta \alpha_s G_s A = (0.553-0.001 T_p_1)\alpha_s G_s A \\\\P = (0.553-0.001 *335.05)0.83*700*8 \\\\P = 1013.032 \ W$

(b)the electrical power generated for a breezy winter day

$T_s = T_{\infty} = -15 ^oC = 258 \ k$

$[0.83*700-0.9*5.67*10^{-8}(T_p_2^4-258^4)]-10(T_p_2-258) - (0.553-0.001T_p_2)0.83*700 = 0\\\\8225.81-5.103*10^{-8}T_p_2^4 - 29.419T_p_2 = 0\\\\Apply \ \ iteration \ method \ to \ solve \ for \ T_p_2\\\\T_p_2 = 279.6 \ k$

$P = \eta \alpha_s G_s A = (0.553-0.001 T_p_2)\alpha_s G_s A \\\\P = (0.553-0.001 *279.6)0.83*700*8 \\\\P = 1270.763 \ W$

3 0

3 years ago

Which gas is responsible for polarizination defect?

Alex_Xolod [135]

Answer:

<h3>Hydrogen gas is responsible for polarizination defect.</h3>

3 0

3 years ago

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