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Flauer [41]
3 years ago
10

PLEASE HELP ):

Physics
1 answer:
jolli1 [7]3 years ago
6 0

The first thing we must do for this case is the sum of forces in a horizontal direction.

We have then:

F1 + F2 = m * a

Substituting values we have:

50 + 75 = m * 2.5

From here, we clear the mass of the object:

m * 2.5 = 125\\m = 125 / 2.5\\m = 50 Kg

We now look for the weight of the object.

W = m * g

Where,

g: acceleration of gravity (9.8 m/s^2)

Substituting values:

W = 50 * 9.8\\W = 490 N

Answer:

the weight of the object is:

W = 490 N

option 4

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In the sport of parasailing, a person is attached to a rope being pulled by a boat while hanging from a parachute-like sail. A r
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Answer:

570 N

Explanation:

Draw a free body diagram on the rider.  There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.

The rider is moving at constant speed, so acceleration is 0.

Sum of the forces in the x direction:

∑F = ma

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Sum of the forces in the y direction:

∑F = ma

F sin 30° - W - T sin 15° = 0

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Substituting:

W = (T cos 15° / cos 30°) sin 30° - T sin 15°

W = T cos 15° tan 30° - T sin 15°

W = T (cos 15° tan 30° - sin 15°)

Given T = 1900 N:

W = 1900 (cos 15° tan 30° - sin 15°)

W = 570 N

The rider weighs 570 N (which is about the same as 130 lb).

6 0
3 years ago
Two 1.0 cm * 2.0 cm rectangular electrodes are 1.0 mm apart. What charge must be placed on each electrode to create a uniform el
kvv77 [185]

Answer:

The number of electrons that must be moved from one electrode to the other to accomplish this is 1.4 X 10⁹ electrons.

Explanation:

<u>Step 1:</u> calculate the charge on each electrode

Given;

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The distance between the electrode = 1mm = 1 X 10⁻³ m

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E =\frac{Kq}{r^2}

where;

E is the electric field strength = 2.0 X 10⁶ N/C

K is coulomb's constant = 8.99 X 10⁹ Nm²/C²

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q is the charge in each electrode = ?

q = \frac{Er^2}{K} = \frac{(2X10^6)(1X10^{-3})^2}{8.99 X10 ^9} = 0.2225 X 10⁻⁹ C

The charge on each electrode is 0.2225 X 10⁻⁹ C

<u>Step 2:</u> calculate the number of electrons to be moved from one electrode to the other.

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= (0.2225 X 10⁻⁹)/(1.602 X 10⁻¹⁹)

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8 0
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