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spayn [35]
2 years ago
12

The passengers are facing forward in the direction that the train is moving. What will happen to the passengers sitting on a tra

in if the train comes to a sudden stop? fall Question 13 options: They will feel a force pushing them downward. They will feel the force pushing them upward. Their bodies will move backwards. Their bodies will move forward.
Physics
1 answer:
marysya [2.9K]2 years ago
6 0

Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.

<h3>What is force of inertia?</h3>

Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.

Given infroamtion-

The passengers are facing forward in the direction that the train is moving.

The train comes to a sudden stop.

Lets see what happens step wise-

  • Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.

  • Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.

  • Thus all the passenger will tend to move in the direction as they are still travelling.

Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.

Learn more about the force of inertia here;

brainly.com/question/10454047

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A student standing on a cliff that is a vertical height d = 8.0 m above the level ground throws a stone with velocity v0 = 22 m/
Alina [70]

Answer:

V = 25.3 , θf = 36.7° below the horizontal

Explanation:

Given Vo = 22m/s , θ = 23°

Vx = VoCosθ

Vy = VoSinθ – gt

t = total time of flight

5 0
3 years ago
An elevator of massmis initially at rest onthe first floor of a building. It moves upward,and passes the second and third floors
Varvara68 [4.7K]

To solve this problem it is necessary to apply the concepts of Work. Work is understood as the force applied to travel a determined distance, in this case the height. The force in turn can be expressed by Newton's second law as the ratio between mass and gravity, as well

W = mgh

Where,

m = mass

h = height

g = Gravitational constant

When it ascends to the second floor it has traveled the energy necessary to climb a height, under this logic, until the 4 floor has traveled 3 times the height h of each of the floors therefore

h = 3h

Replacing in our equation we have to

W = mgh\\W = mg(3h)\\W = 3mgh

The correct answer is 4.

7 0
3 years ago
A person pushes a 50kg box to the right with 100N of force at a constant velocity of 5m/s. Calculate the coefficient of friction
Anna11 [10]
The weight of the box is 50x9.8 = 490 N. The force of friction is 100N. F= μΝ so coefficient = 100/490 = 0.20
8 0
3 years ago
Which is the wavelength of a wave that travels at a speed of 3.0 × 10^8 m/s and has a frequency of 1.5 × 10^16 Hz?
k0ka [10]

Answer:

2 x 10^-8

Explanation:

the formula of wavelength is

the speed divided by frequency

so you have the speed given = 3.0x10^8m/s

and frequency = 1.5×10^16 Hz

so wavelength = 3.0x10^8m/s / 1.5x10^16 Hz

7 0
2 years ago
On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
Luda [366]

Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

Initial position = 60 km/h x 1 hour = 60 km

final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

V_{avg} = \frac{Final \ position\  - \ Initial \ position}{final \ time\  - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\  - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr

Therefore, the average velocity is 180 km/hr

3 0
3 years ago
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