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spayn [35]
2 years ago
12

The passengers are facing forward in the direction that the train is moving. What will happen to the passengers sitting on a tra

in if the train comes to a sudden stop? fall Question 13 options: They will feel a force pushing them downward. They will feel the force pushing them upward. Their bodies will move backwards. Their bodies will move forward.
Physics
1 answer:
marysya [2.9K]2 years ago
6 0

Passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.

<h3>What is force of inertia?</h3>

Force of inertia is the force which acts in the opposite direction of the force of acceleration acting on the body.

Given infroamtion-

The passengers are facing forward in the direction that the train is moving.

The train comes to a sudden stop.

Lets see what happens step wise-

  • Here, the train in moving in the forward direction and the passengers are also facing forward in the direction that the train is moving.

  • Now the train comes to a sudden stop. By this sudden stop the train stops suddenly but all the object including the passengers is still travelling forward due to the inertia force.

  • Thus all the passenger will tend to move in the direction as they are still travelling.

Hence, passengers which are facing forward in the direction that train is moving, their bodies will move forward in application of sudden stop of train.

Learn more about the force of inertia here;

brainly.com/question/10454047

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Is it possible that a speed of 254 and a speed of 100 could be the same speed?
EastWind [94]
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4 0
3 years ago
A wheel, starting from rest, rotates with a constant angular acceleration of 1.80 rad/s^2. During a certain 7.00 s interval, it
lora16 [44]

Answer:

a) 1.3 rad/s

b) 0.722 s

Explanation:

Given

Initial velocity, ω = 0 rad/s

Angular acceleration of the wheel, α = 1.8 rad/s²

using equations of angular motion, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

where

θ2 - θ1 = 53.2 rad

t2 - t1 = 7s

substituting these in the equation, we have

θ2 - θ1 = ω(0)[t2 - t1] + 1/2α(t2 - t1)²

53.2 =ω(0) * 7 + 1/2 * 1.8 * 7²

53.2 = 7.ω(0) + 1/2 * 1.8 * 49

53.2 = 7.ω(0) + 44.1

7.ω(0) = 53.2 - 44.1

ω(0) = 9.1 / 7

ω(0) = 1.3 rad/s

Using another of the equations of angular motion, we have

ω(0) = ω(i) + α*t1

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1.3 = 1.8 * t1

t1 = 1.3/1.8

t1 = 0.722 s

5 0
3 years ago
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