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Pachacha [2.7K]
3 years ago
7

What’s the area of a circle that’s 11 meters

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0

Answer: 380.13271108436 meters2

Step-by-step explanation: This would be the answer if it was radius

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The total cost of 2 bracelets and 3 necklaces is $15.50. The total cost of 4 bracelets and 1 necklace is $13.50. Let b represent
Kaylis [27]

Answer:

A

$2.50

Step-by-step explanation:

b = cost of bracelet

n = cost of necklace

2b+3n = 15.50

4b+1n = 13.50

Multiply the first equation by -2

-4b -6n = -31

4b +n = 13.50

---------------------------

-5n = -17.50

Divide each side by -5

-5n/-5 = -17.5/-5

n = 3.50

Now we can find b

4b+n = 13.50

4b+3.50 = 13.50

4b+3.50-3.50 = 13.50 -3.50

4b = 10

Divide by 4

4b/4 = 10/4

b = 2.50

4 0
3 years ago
6. Many American cars feature speedometers
jarptica [38.1K]

Answer:

500km

Step-by-step explanation:

Let the journey covered in kilometers be A

Since

1 km = 1 mile

x km = 500 miles

Cross multiply

X km x 1 = 500 miles x 1 km

X = 500km

The journey covered in kilometers will be 500km

7 0
3 years ago
1. Find the value of each expression. Show your work.
Mashcka [7]
Are the decimal points supposed to be multiplication symbols?
7 0
3 years ago
Read 2 more answers
How do I show my work to convert 3 lbs to kilograms?
ra1l [238]
One pound is equal to 0.453592 kilograms.
So 3* 0.453592=1.360776 kg


4 0
3 years ago
A collection of coins consists of nickels, dimes, and quarters. There are three fewer quarters than nickels and six more dimes t
weeeeeb [17]

Answer:

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

"There are three fewer quarters than nickels": n - 3 = q

"six more dimes than quarters": q + 6 = d

So now you have three equations with three variables, all you need to do is solve.

\left \{ {{4.35 = 0.25q + 0.10d + 0.05n} \atop {n - 3 = q}} \atop {q + 6 = d}}\right.

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

\left \{ {{4.35=0.25(n-3)+0.10d+0.05n} \atop {(n-3)+6=d}} \right.

You now only have two equations and two variables.

Simplify:

\left \{ {{4.35=0.25n-0.75+0.10d+0.05n} \atop {n+3=d}} \right.

\left \{ {{4.35=0.30n-0.75+0.10d} \atop {n+3=d}} \right.

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

4.35=0.40n-0.45

4.35+0.45=0.40n

4.80=0.40n

n=12

You have 12 nickels. Now sub "n" back into your equations to find the number of dimes and quarters:

n - 3 = q

12 - 3 = q

q = 9

You have 9 quarters.

q + 6 = d

9 + 6 = d

d = 15

You have 15 dimes.

3 0
3 years ago
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